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wariber [46]
3 years ago
7

Solve for x. Use the completing the square method. x² + 10x = 6

Mathematics
1 answer:
wel3 years ago
6 0

Answer:

x =5 ±sqrt( 31)

Step-by-step explanation:

x² + 10x = 6

b = 10

Take b/2 and square it

(10/2) = 5  5^2 = 25

Add 25 to each side

x² + 10x+25 = 6+25

The left side will be (x+b/2)^2

(x+5)^2 = 31

Take the square root of each side

sqrt((x+5)^2) = ±sqrt( 31)

x+5 = ±sqrt( 31)

Subtract 5 from each side

x+5-5 = -5 ±sqrt( 31)

x =5 ±sqrt( 31)

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After triangle ACE is dilated by a factor of 6, it has an area of 180 square inches. What was its area before dilation?
Agata [3.3K]

Answer:

The area of triangle ACE before dilation is:  30 square inches

Step-by-step explanation:

We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.

  • If the scale factor > 1, the image is enlarged
  • If the scale factor is between 0 and 1, it gets shrunk
  • If the scale factor = 1, the object and the image are congruent

The length of the image can be determined by multiplying the length of the original point by a certain scale factor.

Given that after triangle ACE is dilated by a factor of 6, it has an area of 180 square inches.

Thus, it means the dilated area is 6 times the area before dilation.

Let x be the pre-dilation area

As the dilated area is 6 times the area before dilation, so

6x = 180

divide both sides by 6

6x/6 = 180/6

x = 30 square inches.

Therefore, the area of triangle ACE before dilation is:  30 square inches

4 0
3 years ago
Can somebody help me please
Sergeu [11.5K]
Area = length x width

24 = (n-3) x 2
24 = 2n -6
2n = 30
n = 15

Length is 15-3 =12, width is 2
24 = 12 x 2
3 0
3 years ago
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2. Since these two triangles, namely, EFH and GFH share the same segment (HF), this side is also congruent to these two triangles.

3. Since EH is congruent to HG, and FH is congruent to itself, then EF is congruent to GF.

4. Angle E is congruent to angle G.

Therefore, we can say that:

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We can conclude that the congruence rule, in this case, is SAS (Side-Angle-Side), because<em> if two sides and the included angle are congruent to the corresponding parts of the other triangle, the triangles are congruent.</em>

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Likewise, we can also conclude that the triangle EFH is congruent to triangle GFH.

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