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mart [117]
3 years ago
7

Please help!! Find the value of x to the nearest tenth.

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
8 0

Answer:is it 1

Step-by-step explanation:

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How do I write 360,556 in expanded form
Varvara68 [4.7K]
360.556=3*100.000+6*10.000+5*100+5*10+6
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What is the value of 11−3m , when m = 2?
user100 [1]
When a number is next to a letter like so: 3m You would multiply, so 
3 ~ 2 = 6 then solve the problem like this

11-3m= ?
3~2=6
6-11=5
so 11-3m=5
 Hope this helps! :)


4 0
4 years ago
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HELP ME PLEASE I WILL PUT U AS BRILLIANT
Mandarinka [93]

Answer:

2 and 1/4

Step-by-step explanation:

3.5 - 1.25 = 2.25

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7 0
3 years ago
Calculate all four second-order partial derivatives and confirm that the mixed partials are equal. f(x,y)= 2e^xy
nadya68 [22]
ANSWER TO QUESTION 1

The given function is

f(x,y)=2 {e}^{xy}

The partial derivative of f with respect to x means we are treating y as a constant. The first derivative is

f_{x} = 2y {e}^{xy}

and the second derivative with respect to x is,

f_{xx} = 2 {y}^{2} {e}^{xy}

ANSWER TO QUESTION 2

The given function is

f(x,y)=2 {e}^{xy}

The partial derivative of f with respect to y means we are treating x as a constant. The first derivative is

f_{y} = 2x{e}^{xy}

and the second derivative with respect to y is

f_{yy} = 2 {x}^{2} {e}^{xy}

ANSWER TO QUESTION 3

Our first mixed partial is

f_{xy}

We need to differentiate
f_{x} = 2y {e}^{xy}
again. But this time with respect to y.

Since this is a product of two functions of y, we apply the product rule of differentiation to obtain,

f_{xy} = 2y( {e}^{xy})' + ({e}^{xy})(2y)'

f_{xy} = 2xy {e}^{xy} + 2{e}^{xy}

ANSWER TO QUESTION 4

The second mixed partial is

f_{yx}

We need to differentiate
f_{y} = 2x{e}^{xy}

again. But this time with respect to x.

Since this is a product of two functions of x, we apply the product rule of differentiation to obtain,


f_{yx} = 2x({e}^{xy})' + ({e}^{xy})(2x)'

f_{yx} = 2xy {e}^{xy} + 2{e}^{xy}

Hence,

f_{xy} = 2xy {e}^{xy} + 2{e}^{xy} =f_{yx}
4 0
3 years ago
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