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N76 [4]
3 years ago
8

Points A, B, and C are collinear, and B lies between A and C. If AC = 48, AB = 2x+2, and BC = 3x+6, what is BC?

Mathematics
2 answers:
Vesna [10]3 years ago
8 0

Answer:

The value of BC is 30.

Step-by-step explanation:

Given information: A, B, and C are collinear, B lies between A and C, AC = 48, AB = 2x+2, and BC = 3x+6.

If A, B, and C are collinear, B lies between A and C, then by using segment addition property, we get

AB+BC=AC

Substitute AC = 48, AB = 2x+2, and BC = 3x+6 in the above equation.

(2x+2)+(3x+6)=48

On combining like terms we get

(2x+3x)+(2+6)=48

5x+8=48

Subtract 8 from both sides.

5x=48-8

5x=40

Divide 5 from both sides.

x=8

The value of x is 8.

We need to find the value of BC.

BC=3x+6\Rightarrow 3(8)+6=30

Therefore the value of BC is 30.

aleksandr82 [10.1K]3 years ago
4 0

Answer:

BC=30

Step-by-step explanation:

AC = 48

AB = 2x+2

BC=3x+6

AC= AB + BC

48 = 2x+2+3x+6

48=5x+8

5x=40

x=8

Hence

BC = 3(8)+6

BC=24+6

BC=30

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