0.13 and the amount of digits are 1 because there is only a repeating 3.
Answer:
<u>The correct answer is r = ∛GM*T²/4π²</u>
Step-by-step explanation:
Let's rewrite the formula to find the period of orbit of a satellite around a planet, to solve for r, this way:
T^2=(4pi^2/GM)r^3
T² = (4π²/GM) * r³
r³ = T²/ (4π²/GM)
r³ = T² * GM/4π²
r³ = GMT²/4π²
∛r³ = ∛GM*T²/4π²
r = ∛GM*T²/4π²
<u>The correct answer is r = ∛GM*T²/4π²</u>
Answer:
p = 2 ; q = 4
Step-by-step explanation:
Given tbe equation :
3p + 2q = 14 - - - (1)
10p + 6q = 44 - - -(2)
What is p and what is q
This is a simultaneous equation ; using elimination method :
Multiply (1) by 6 and (2) by 2
18p + 12q = 84 - - - - (3)
20p + 12q = 88 - - - (4)
Subtract (3) and (4)
-2p = - 4
p = 4/2
p = 2
Put p = 2 in (1)
3p + 2q = 14
3(2) + 2q = 14
6 + 2q = 14
2q = 14 - 6
2q = 8
q = 8/2
q = 4
p = 2 ; q = 4
Answer:
x=1y
Step-by-step explanation:
Answer:
x² - 5x = 14
x = -2 or x = 7
Step-by-step explanation:
x² - 5x = 14
x² - 5x - 14 = 0
(x+2)(x-7) = 0
x = -2 or x = 7
