The number of additional sandwiches is 15.
If we multiply 75 sandwiches by 0.2 (20%), then we get 15, which would be the number of sandwiches needed to be sold to meet the sales goal.
Hope this helped.
-8 has a multiplicity of 3
3 has a multiplicity of 1
Let 
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so
where 
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is
where 
denotes the CDF of , and 
denotes the inverse CDF. We have
Similarly, because 20% of students obtain less than 40 marks, we have
so that
Then 
are such that
and we find
No because
15b + 4 = 25.6
15b = 21.6
b = 1.44
0.6+15b+4 = 25.6
4.6 + 15b = 25.6
15b = 21
b = 1.4
The answers are not the same therefore they are not equivalent.
Answer:15x
Step-by-step explanation:you add 12 + 3 which equals 15 and then you just carry the x over
