#4 is 47, 48, 49
47+48+49=144
In this situation, it is similar to a coin flip, so think about flipping a 2 sided chip, one side colored yellow the other blue, flipping the chip will result in a 50/50 chance for it to land on either side, so no matter how many times you flip it it will always be a 1/2 chance of it being on one of the sides
Y2-y1=m(x2-x1)
Y- (-3)=1/3(x-3)
Answer:
How many general admission tickets were purchased? __<u>136</u>__
How many upper reserved tickets we purchased? _<u>300</u>_
Step-by-step explanation:
Let the number of general tickets = g.
Let the number of reserved tickets = r.
6.5g + 8r = 3284
g + r = 436
6.5g + 8r = 3284
(+) -8g + -8r = -3488
--------------------------------
-1.5g = -204
g = 136
g + r = 436
136 + r = 436
r = 300
Answer:
How many general admission tickets were purchased? __<u>136</u>__
How many upper reserved tickets we purchased? _<u>300</u>_
Answer:
f = 1
Step-by-step explanation:
Use the method of cross- multiplication
=
⇒ ad = bc, thus
20f = 5(f + 3) ← distribute
20f = 5f + 15 ( subtract 5f from both sides )
15f = 15 ( divide both sides by 15 )
f = 1