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3 years ago

What is the product? (-2x-9y^2) (-4x-3) URGENT

Mathematics

1 answer:

Murljashka [212]3 years ago

4 0

Answer:

8x^2 + 6x + 36xy^2 + 24y^2

Step-by-step explanation:

First, multiply the two terms inside the second set of parentheses by-2x; we get 8x^2 + 6x.

Next, multiply the same two terms by -9y^2; we get 36xy^2 + 24y^2.

Now add these products together:

8x^2 + 6x + 36xy^2 + 24y^2 This is the desired product.

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Find x step by step (10 points)

AleksandrR [38]

Answer:

$\sqrt{(n-m)(n+m)}$ & $-\sqrt{(n-m)(n+m)}$

Step-by-step explanation:

1) Subtract $m^{2}$ from both sides. This should leave you with $x^{2}=n^{2}-m^{2}$ .

2) Square root both sides. This should leave you with $x=\sqrt{n^2-m^2}$ & $x=-\sqrt{n^2-m^2}$ .

<em>You can stop here if this is what the problem is asking for. However, it is not fully simplified.</em>

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3) Factor the equation. This should leave you with $\sqrt{(n-m)(n+m)}$ & $-\sqrt{(n-m)(n+m)}$ .

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2 years ago

Read 2 more answers

Gerogia is selling ice cream from her store at the beach. She opens the day with 500 servings of ice cream. Durning the day she

hram777 [196]

Answer:

325

Step-by-step explanation:

65% of 500 is 325

5 0

3 years ago

Write the product (4 + i)(4 − i) in the form a + bi. A. 16 − i B. 16 − i2 C. 17 D. 8

bonufazy [111]

Answer:

A.16–i is correct.

Step-by-step explanation:

(4+i)(4–i). [(a+b)(a–b)=(a²–b²)]

(4²–i²)=16–i

I hope this answer is correct so please vote my answer

3 0

3 years ago

A drug company claims that fewer than 1% of pills that it produces and ships fail to retain full potency after 60 days of produc

Harlamova29_29 [7]

4% of the 200 pills failed to retain full potency after 60 days.

8 0

3 years ago

Use the given values of n= 93 and p= 0.24 to find the minimum value that is not significantly low, μ- 2σ , and the maximum val

allsm [11]

Answer:

The answer is "Option a".

Step-by-step explanation:

$n= 93 \\\\p= 0.24\\\\\mu=?\\\\ \sigma=?\\\\$

Using the binomial distribution: $\mu = n\times p = 93 \times 0.24 = 22.32\\\\\sigma = \sqrt{n \times p \times (1-p)}=\sqrt{93 \times 0.24 \times (1-0.24)}=4.1186$

In this the maximum value which is significantly low, $\mu-2\sigma$ , and the minimum value which is significantly high, $\mu+2\sigma$ , that is equal to:

$\mu-2\sigma = 22.32 - 2(4.1186) = 14.0828 \approx 14.08\\\\\mu+2\sigma = 22.32 + 2(4.1186) = 30.5572 \approx 30.56$

3 0

3 years ago