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daser333 [38]
2 years ago
15

Lee wants to buy two pairs of shoes. One pair costs $37.07 and the other pair costs $42.48. A pair of socks cost $8.50. If Lee b

uys both pairs of shoes and the two pairs of socks, how much money will he need.
Mathematics
1 answer:
daser333 [38]2 years ago
5 0

Answer:

$96.55

Step-by-step explanation:

The computation of the money he would require is shown below:

Since lee wants to buy both pairs of shoes and the two pairs of socks

So the amount of money he needed is

= $37.07 + $42.48 + 2 × $8.50

= $37.07 +  $42.48 + $17

= $96.55

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Isaiah has $7.15 in Dimes and Nickels. He has a total of 91 coins. How many of each coin does he have? Group of answer choices d
yarga [219]

Answer:

Dimes = x = 52

Nickels = y = 39

Step-by-step explanation:

Let

Dimes = x

Nickels = y

x + y = 91 (1)

0.10x + 0.05y = 7.15 (2)

From (1)

x = 91 - y

Substitute x = 91 - y into (2)

0.10x + 0.05y = 7.15

0.10(91 - y) + 0.05y = 7.15

9.10 - 0.10y + 0.05y = 7.15

- 0.10y + 0.05y = 7.15 - 9.10

-0.05y = -1.95

y = -1.95 / 0.05

= 39

Substitute y = 39 into (1)

x + y = 91

x + 39 = 91

x = 91 - 39

x = 52

Dimes = x = 52

Nickels = y = 39

7 0
3 years ago
In a class of 32 students, 4 have birthdays in October.What percent have October birthdays
natta225 [31]

Answer:

12.5% of students

Step-by-step explanation:

To find this you would divide 4 by 32 (4/32) and get 0.125. To find a percent, you multiply by 100 and get 12.5%

3 0
2 years ago
Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that s
WINSTONCH [101]

Answer:  \bold{c=\dfrac{1+\sqrt{19}}{3}\approx1.8}

<u>Step-by-step explanation:</u>

There are 3 conditions that must be satisfied:

  1. f(x) is continuous on the given interval
  2. f(x) is differentiable
  3. f(a) = f(b)

If ALL of those conditions are satisfied, then there exists a value "c" such that c lies between a and b and f'(c) = 0.

f(x) = x³ - x² - 6x + 2     [0, 3]

1. There are no restrictions on x so the function is continuous \checkmark

2. f'(x) = 3x² - 2x - 6 so the function is differentiable \checkmark

3. f(0) =  0³ - 0² - 6(0) + 2 = 2

   f(3) =  3³ - 3² - 6(3) + 2  = 2

   f(0) = f(3) \checkmark

f'(x) = 3x² - 2x - 6 = 0

This is not factorable so you need to use the quadratic formula:

x=\dfrac{-(-2)\pm \sqrt{(-2)^2-4(3)(-6)}}{2(3)}\\\\\\.\quad =\dfrac{2\pm \sqrt{4+72}}{2(3)}\\\\\\.\quad =\dfrac{2\pm \sqrt{76}}{2(3)}\\\\\\.\quad =\dfrac{2\pm 2\sqrt{19}}{2(3)}\\\\\\.\quad =\dfrac{1\pm \sqrt{19}}{3}\\\\\\.\quad \approx\dfrac{1+4.4}{3}\quad and\quad \dfrac{1-4.4}{3}\\\\\\.\quad \approx1.8\qquad and\quad -1.1

Only one of these values (1.8) is between 0 and 3.

5 0
2 years ago
A symbol used to name one or more parts of a whole or asset or a location on the number line is a
r-ruslan [8.4K]

Answer:

<h2><u>Fraction</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u></h2>

7 0
3 years ago
Write 5 5/6 as an improper fraction
Romashka-Z-Leto [24]

Answer:

the answer is 35/6 hope it helps:)

4 0
2 years ago
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