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Andrews [41]
3 years ago
10

23+4y=63 what does y equal?

Mathematics
1 answer:
Sladkaya [172]3 years ago
5 0

Answer:

y=10

Step-by-step explanation:

1. Make sure that the variable is left alone on the other side of the equal sign

2. remove all the no. on the variable side

3. subtract 23 from both sides hence left with 4y

4. divide the 40 u by 4 hence giving u 10

DONE

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True or false a system of equations including a line and a parabola can have only 2 solutions
Sergio [31]
False, it can have none when the line does not touch the parabola, one when the line touches at one point, and 2 when the line intersects in two places.
3 0
3 years ago
For f(x) = 2x+3 which represents f(x) when x= 6?<br><br> A.16<br> B.20<br> C.28<br> D.96
yawa3891 [41]

Answer:

15

Step-by-step explanation:

when x=6 plug it in to the equation and you would get 2(6)+3 which is 12+3 which is 15

7 0
3 years ago
Please anyone solve this for me..No spam.​
Tamiku [17]

Answer:

  • 3096

Step-by-step explanation:

<u>Given:</u>

  • 3x-\frac{1}{4y}=24

<u>Rewrite it as:</u>

  • 3x=\frac{1}{4y}+24
  • x=\frac{1}{12y}+8

<u>Simplify the expression:</u>

  • 8x(6x - \frac{1}{y} ) + \frac{1}{12y^2} (4 - 3y + 36xy^2) =
  • 8(\frac{1}{12y}+8)(6(\frac{1}{12y}+8) - \frac{1}{y} ) + \frac{1}{3y^2}  - \frac{1}{4y}  + 3x =
  • 8(\frac{1}{12y}+8)(48- \frac{1}{2y} ) + \frac{1}{3y^2}  - \frac{1}{4y}  + 24 + \frac{1}{4y}  =
  • 8(\frac{4}{y}+8*48- \frac{1}{24y^2} -\frac{4}{y} ) + \frac{1}{3y^2}  + 24  =
  • 8(384-\frac{1}{24y^2}) + \frac{1}{3y^2}  + 24  =
  • 8*384-\frac{1}{3y^2} + \frac{1}{3y^2}  + 24  =
  • 3072+24=
  • 3096
3 0
2 years ago
How do solve this equation step by step
Kryger [21]

Answer: 15n³-105n²+2n+16/6n²-42n

Step-by-step explanation:

n+8/3n²-21n +5n/2

2(n+8)+5n(3n²-21n)/2(3n²-21n)

2n+16+15n³-105n²/6n²-42n

15n³-105n²+2n+16/6n²-42n

7 0
4 years ago
10.1 and 10.15 witch one is greater
RUDIKE [14]

Answer:

10.15

Step-by-step explanation:

Subtract:

10.15 - 10.1 = 0.05

10.15 is greater than 10.1 by 0.05

~

6 0
3 years ago
Read 2 more answers
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