Answer:
a=2.5
Step-by-step explanation:
3a-2.4=5.1 Add the like terms ( plus 2.4 cancels out -2.4)
+2.4 +2.4
3a=7.5 Now divide by 3
/3 /3
a=2.5
Answer:
L = 3√5
Step-by-step explanation:
A square and a rectangle have equal areas.
Area of a square = Area of a rectangle
L² = H * W
If the dimensions of the rectangle are 15 units by 3 units,
L² = 15 * 3
L² = 45
Determine the length of the side of the square.
L = √45
L = 3√5
Answer:
They are both due to the wave nature of light.
Answer:
The perpendicular line would be y = -3x - 7
Step-by-step explanation:
To find the equation of the line, we first need to solve the original line for y.
-x + 3y = 9
3y = x + 9
y = 1/3x + 3
Now we know the slope of the original line to be 1/3. Since perpendicular lines have opposite and reciprocal slope, we know the new line to have a slope of -3. We can then use that along with the given point in point-slope form to find the equation.
y - y1 = m(x - x1)
y - 2 = -3(x + 3)
y - 2 = -3x - 9
y = -3x - 7
Answe
Given,
f(x) = 49 − x² from x = 1 to x = 7
n = 4
For x= 1
f(x₀) = 49 - 1^2 = 48
x = 2.5
f(x₁) = 42.75
x = 4
f(x₂) = 49 - 4^2 = 33
x = 5.5
f(x₃) = 49 - 5.5^2 = 18.75
x = 7
f(x₄) = 49 - 7^2 = 0
We have to evaluate the function on therigh hand point
![A = \Delta x [f(x_1)+f(x_2)+f(x_3)+f(x_4)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%2Bf%28x_4%29%5D)
![A = 1.5 [42.75+33+18.75+0]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B42.75%2B33%2B18.75%2B0%5D)
For Area for left hand sum
![A = \Delta x [f(x_0)+f(x_1)+f(x_2)+f(x_3)]](https://tex.z-dn.net/?f=A%20%3D%20%5CDelta%20x%20%5Bf%28x_0%29%2Bf%28x_1%29%2Bf%28x_2%29%2Bf%28x_3%29%5D)
![A = 1.5 [48+42.75+33+18.75]](https://tex.z-dn.net/?f=A%20%3D%201.5%20%5B48%2B42.75%2B33%2B18.75%5D)
