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3 years ago

How to name a ray 3 different ways?

1 answer:

5 0

1)A ray has one endpoint and extends indefinitely in one direction.
2)A pair of opposite rays are two rays that have the same endpoint and extend in opposite directions.
3)Rays are always named with two points and the first point in the name must be the endpoint.

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I need help on 9-11 please

lisabon 2012 [21]

Hello! I would love to help!

9. Basically, it is asking us to multiply 5.2 by 46.

5.2*46=239.2

So, your answer is 239.2 inches.

10. First, let's find out how many blocks she has left to run by subtracting the number of blocks she has already ran by the number of total blocks.

60-18=42

So Susan has 42 blocks left to run. Now, let's divide that by 2 since she can run 2 blocks per minute.

42/2=21

So, the answer is 21 minutes.

11. Let's set up an equation: We know that she will automatically pay $49.95 per month, plus $0.15 per additional minute. We also know her final total for the month was $61.20:

49.95+0.15m=61.20

Let's solve! Subtract both sides by 49.95

49.95+0.15m-49.95=61.20-49.95

Simplify

0.15m=11.25

Now, divide both sides by 0.15

0.15m/0.15=11.25/0.15

M=75

So your answer is 75 additional minutes.

Hope this helped! Comment if you have questions!

5 0

3 years ago

Find dy/dx if y =x^3+5x+2/x²-1

stiks02 [169]

Differentiate using the Quotient Rule –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

f(x) = x^3+5x+2
g(x) = x^2-1

Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

7 0

2 years ago

The events A and B are mutually exclusive. If P(A)=0.1 and P(B)=0.4, what is P(A or B)? ASAP

Gemiola [76]

Answer:

Given that the events A and B are mutually exclusive.

P(A) = 0.1

P(B) = 0.4

Mutually Exclusive Events: When two events are Mutually Exclusive it is impossible for them to happen together i.e

If A and B are two events then; P(A and B) = 0

then;

P(A or B) = P(A) +P(B)

By the definition of mutually exclusive events;

P(A or B) = P(A) +P(B) ......[1]

Substitute the values of P(A) = 0.1 and P(B) = 0.4 in [1] we have;

P(A or B) = P(A) +P(B) = 0.1+0.4 = 0.5

6 0

3 years ago

Determine the absolute value of -11.

AURORKA [14]

The absolute value is how far a number is from zero. The number will always be positive unless there is a negative symbol outside of the brackets. Therefore, your answer is 11.

5 0

3 years ago

Read 2 more answers

in recent year, the world production of wheat was about 5.2 *10^8 metric tons. Canada produced 1/25 of this wheat. about how muc

liubo4ka [24]

To find wheat produced by Canada we have to multiply 5.2*10^8 times 1/25
So 5.2*10^8*1/25=20 800 000= 2.08*10^5 metric tons. - the result.

7 0

2 years ago