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Katena32 [7]
3 years ago
8

Find the exact value: tan40/cot50 sec55/csc35 SHOW ALL WORK!

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0
These are the important trigonometric relations to base on:

cot (x) = 1/tan(x)
sec(x) = 1/cos(x)
csc(x) = 1/sin(x)

Following these properties, we could simplify the equation and input into the calculator to determine the exact value.

<span>tan40/cot50 = tan40/(1/tan50) = tan40tan50 = 1

</span><span>sec55/csc35 = (1/cos 55)/(1/sin 35) = sin35/cos55 = 1</span>
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Given that 5x:9=7:3 calculate the value of x. give your answer in its simplest form.
Hitman42 [59]

\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} →}

<h3>x = 21/5</h3>

Step-by-step explanation:

<h3>___________________________</h3>

<h3>Given →</h3>

5x:9 = 7:3

<h3>So,</h3>

→ 5x/9 = 7/3

→ x = (7 × 9)/(3 × 5)

→ x = 21/5

<h3>___________________________</h3>

<h3>Hope it helps you!!</h3>
8 0
1 year ago
What is the area of the circle whose equation is (x − 9)2 + (y − 3)2 = 64?
aalyn [17]
(x-xo)²+(y-yo)²=r²
(x-9)²+(y-3)²=64
r²=64
Area of a circle=πr²=3.14×64=200.96
7 0
2 years ago
A geologist has two rocks on a scale that weighs 2 1/2 pounds together rock A was 1/7 of the total weight. How much did rock A w
jarptica [38.1K]
5/14 is the answer. I'll do my best bud
Answer↑

Steps↓
Convert 2 1/2 to an improper fraction:
2 + 2+ 1 over 2

Once you add the numbers, that will be 5/2.

Now, multiply that with 1/7:
5/2 • 1/7

Your answer will be 5/14

Therefore, Rock A weighs 5/14 pounds
7 0
3 years ago
A line is represented by the equation y = 3x - 6. Which is a coordinate of a
Furkat [3]

Answer:

(2,0)

Step-by-step explanation:

Simply plug in the coordinates. y= 3x - 6, so in this case 0= 3(2) - 6 or 0=0, making the point on the line. If the equation is not true like when using (0,3) and getting 3= -6, then the point is not on the line.

6 0
2 years ago
Which of the following could be the perimeter of a rectangle with an area of 16 square inches?
Butoxors [25]

no doubt it's 16 inches

8 0
3 years ago
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