Since we know that they have to e similar, it is a 20ft tall flagpole. the shadow of the girl is half of her height, so since the flag pole shadow is 10ft it is simple 10 multiplied by 2
21 /3 = 7
35 / 5 = 7
63 / 9 = 7
his rate is B. 7 yds/sec
Let the faculties be X and the number of students be Y.
X/Y = 17/3
3X= 17Y
X=17Y/3
Let that be equation 1
We also know that X+Y = 740. Let it be equation 2
Substitute equation 1 in equation 2
(17Y/3)+Y= 740
20Y/3 = 740
Y=111
Since the total is 740, then X equal 740-111 =629.
The number of faculties is 111 and the number of students is 629.
Answer:
h(-5) = 34
Step-by-step explanation:
h(x) = -5x + 9
h(-5) = -5(-5) + 9 = 25 + 9 = 34
<u>Answer:</u>
It's X=2
<u>Working out:</u>
<u>(left one):</u>
2(x+3)=10
2x+6=10
2x=10-6
2x=4
x=2
Working out:
(right one):
2(x+3) must be all divided by 2 so it will be x+3 and same for 10, it will be 5 so...
x+3=5
x=5-3
x=2
Hope it helps ^---^
