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nordsb [41]
3 years ago
13

6(7a-10) how do I solve this

Mathematics
2 answers:
NeTakaya3 years ago
7 0
6(7a-10) \\ \\ 6 \times 7a + 6 \times -10 \ / \ distribute \\ \\ 42a + 6 \times -10 \ / \ simplify \\ \\ 42a + -60 \ / \ simplify \\ \\ 42a - 60 \ / \ simplify \\ \\ Answer: \fbox {42a - 60}
Masteriza [31]3 years ago
6 0
Solve the brackets, to do that you should multiply the numbers inside the bracket with the first number outside and in the right to the brackets.so,

6(7a-10)= 42a-60
hence the answer is, 42a-60
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Work out m and c for the line: 3 y + 6 x = − 3
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Answer:

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Step-by-step explanation:

• Let's first phrase out the general equation of a line

{ \rm{y = mx + c}}

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[ remember that a general line equation must be in slope - intercept form as shown above ]

• from our question, we are given the equation;

{ \rm{3y + 6x =  - 3}}

• let's make y the subject in order to make the equation in slope - intercept format.

→ <em>r</em><em>e</em><em>m</em><em>e</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em>t</em><em>o</em><em> </em><em>a</em><em>p</em><em>p</em><em>l</em><em>y</em><em> </em><em>"</em><em>s</em><em>u</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>m</em><em>a</em><em>k</em><em>i</em><em>n</em><em>g</em><em> </em><em>k</em><em>n</em><em>o</em><em>w</em><em>l</em><em>e</em><em>d</em><em>g</em><em>e</em><em>"</em>

{ \rm{3y =  - 3 - 6x}} \\  \\ { \rm{3y =  - 6x - 3}} \\  \\ { \rm{ \frac{3y}{3}  =  \frac{ - 6x}{3}  -  \frac{3}{3} }} \\  \\  { \boxed{ \rm{y =  - 2x - 1}}}

• The above boxed equation is now a general equation. Let's extract out slope, m and y-intercept, c

{ \rm{m \:  \dashrightarrow \:  - 2}} \\  \\ { \rm{c \:  \dashrightarrow \:  - 1}}

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Step-by-step explanation:

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Step-by-step explanation:

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