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zheka24 [161]
3 years ago
8

Assume that cans of Coke are filled so that the actual amounts have a mean of 12.00 oz and a standard deviation of 0.11 oz. Find

the probability that a single can of Coke has at least 12.19 oz.
Mathematics
1 answer:
Dvinal [7]3 years ago
8 0

Answer:

0.0421

Step-by-step explanation:

Mean(μ) = 12.00 oz

Standard deviation (σ) = 0.11 oz

Z = (x - μ)/σ

Z = (12.19 - 12.00) / 0.11

Z= 0.19/0.11

Z = 1.727

From the normal distribution table, Z = 1.727 = 0.4579

Φ(Z) = 0.4579

Recall that if Z is positive

Pr(x>a) = 0.5 - Φ(Z)

Pr(x > 12.19) = 0.5 - 0.4579

= 0.0421

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A family is planning a three-week vacation for which they will drive across the country. They have a van that gets 12 miles per
svetoff [14.1K]

Answer:

The family will pay 34722 cents more if they take the van

Step-by-step explanation:

Given

Van = 12 miles per gallon

Sedan = 36 miles per gallon

Distance = 2500 miles

Gas = $2.50 per gallon

First, we need to determine the number of gallons that'll be used by both vehicles

This  is done by dividing total distance by number of miles per gallon

Van = \frac{2500}{12} \ gallon

Sedan = \frac{2500}{36}\ gallon

Next, is to multiply this by the cost of gas per gallon;

This gives the total spendable amount on both vehicles

Van = \frac{2500}{12} * \$2.50

Van = \frac{\$6250}{12}

Van = \$520.833

Sedan = \frac{2500}{36}* \$2.50

Sedan = \frac{\$6250}{36}

Sedan = \$173.611

Next is to get the difference between these amounts

Difference = \$520.833 - \$173.611

Difference = \$347.222

Multiply by 100 to convert to cents

Difference = 347.222 * 100 cents

Difference = 34722.2 \ cents

Difference = 34722\ cents (Approximated)

Hence;

<em>The family will pay 34722 cents more if they take the van</em>

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