Assume that cans of Coke are filled so that the actual amounts have a mean of 12.00 oz and a standard deviation of 0.11 oz. Find
the probability that a single can of Coke has at least 12.19 oz.
1 answer:
Answer:
0.0421
Step-by-step explanation:
Mean(μ) = 12.00 oz
Standard deviation (σ) = 0.11 oz
Z = (x - μ)/σ
Z = (12.19 - 12.00) / 0.11
Z= 0.19/0.11
Z = 1.727
From the normal distribution table, Z = 1.727 = 0.4579
Φ(Z) = 0.4579
Recall that if Z is positive
Pr(x>a) = 0.5 - Φ(Z)
Pr(x > 12.19) = 0.5 - 0.4579
= 0.0421
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