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3 years ago

8

Assume that cans of Coke are filled so that the actual amounts have a mean of 12.00 oz and a standard deviation of 0.11 oz. Find

the probability that a single can of Coke has at least 12.19 oz.

1 answer:

Dvinal [7]3 years ago

8 0

Answer:

0.0421

Step-by-step explanation:

Mean(μ) = 12.00 oz

Standard deviation (σ) = 0.11 oz

Z = (x - μ)/σ

Z = (12.19 - 12.00) / 0.11

Z= 0.19/0.11

Z = 1.727

From the normal distribution table, Z = 1.727 = 0.4579

Φ(Z) = 0.4579

Recall that if Z is positive

Pr(x>a) = 0.5 - Φ(Z)

Pr(x > 12.19) = 0.5 - 0.4579

= 0.0421

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Y = 2x - 4....so sub in 2x - 4 for x in the other equation

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Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

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For this case, we can rewrite the equation as:

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Here $P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}$

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So, we can find:

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To check our solution is right or not, put your y(x) back to the ODE:

$y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}$

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This is one solution, now, let's solve for the other equation:

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Your final answers are:

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