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3 years ago

A rectangle has a length of 28 in and a width of 3ft. what is the perimeter of the rectangle?

Mathematics

1 answer:

finlep [7]3 years ago

5 0

Answer: The answer is 62 ft.

Step-by-step explanation:

To find the perimeter, you do 2 times the width and 2 times the length. 3 times 2 equals 6 and 28 times 2 equals 56. 6+56=62

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PLZ HELP ASAP IM TIMED THX<br><br> FIND AREA

s2008m [1.1K]

Answer: B

Step-by-step explanation:

I used heron's formula.

3 0

3 years ago

Increase 250ml by 86%

Alexandra [31]

250=100%
25=10%
12.5=5%
2.5=1%
25*8=200(80%)
12.5+2.5=15(6%)
200+12=215(86%)
250+200=450(186%)
so 450ml is your answer
Hope this helped :)

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3 years ago

89b - 34 = 411<br> help me new answer

Bess [88]

Answer:

b = 5

Step-by-step explanation:

89b = 411 + 34 (445)

89b = 445

b = 5

3 0

3 years ago

Read 2 more answers

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$