3 years ago

A rectangle has a length of 28 in and a width of 3ft. what is the perimeter of the rectangle?

Mathematics

1 answer:

finlep [7]3 years ago

5 0

Answer: The answer is 62 ft.

Step-by-step explanation:

To find the perimeter, you do 2 times the width and 2 times the length. 3 times 2 equals 6 and 28 times 2 equals 56. 6+56=62

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SVETLANKA909090 [29]

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3 years ago

Help ! solve the following system of equations -9x+2y=-13 2x-9y=20

Stella [2.4K]

Answer: x = 1, y = -2

Step-by-step explanation:

-9x+2y=-13

x= 13/9 + 2/9y

2x-9y=20

2(13/9+2/9y)-9y=20

Substitute y with -2.

x= 13/9+2/9(-2)

After solving you'll see that 1 is a possible solution for x.

Check your answer

-9x+2y=-13

-9x1+2(-2) = -13

2x-9y=20

2x1-9(-2) = 20

-13 = -13

20 = 20

Therefore, x=1 and y=-2

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2 years ago

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Vlada [557]

D) initial value of 60 and multiplying by 1/3

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3 years ago

What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27

malfutka [58]

Answer with explanation:

$\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}$

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0

3 years ago

Read 2 more answers

Y=2X+1 FOR X=-3,-1,0,2

Ahat [919]

When x = -3 y = -5
When x = -1 y = -1
When x = 0 y = 1
When x = 2 y = 5

6 0

3 years ago