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eduard
3 years ago
11

4. You are reading a book that is 268 pages. You have already read 112 pages. You read 39

Mathematics
2 answers:
Neporo4naja [7]3 years ago
8 0

Answer:

i think it is 4

Step-by-step explanation:

bc you do 268-112=156 then you take 156 and divide it by 39 and you end up getting 4.

Andre45 [30]3 years ago
4 0

Answer:

4 days

Step-by-step explanation:

268-112= 156    

156 divided by 39 = 4

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I think it’s C but I’m not too sure
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The ratio of the angles in a triangle is 5:9:10. what is the measure of the largest angle?
Maksim231197 [3]

The measure of the largest angle is 75 degrees.

<h3>What is a triangle? </h3>

A triangle is a polygon with three sides and vertices. The sum of angles in a triangle is 180 degrees. Types of triangles include: right-angled triangle, isosceles triangle, equilateral triangle and scalene triangle.

<h3>What is the measure of the largest angle? </h3>

The measure of the largest angle = (largest ratio / sum of ratios) x 180

10 / 24 x 180 = 75 degrees

Please find attached an image of a triangle. To learn more about a triangle, please check: brainly.com/question/9329354

6 0
3 years ago
A local discount store is famous for their motto, "Shop with us and you'll pay 20% less". Their claim is that every item in the
Darya [45]
Use percentage multipliers:
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Hope This Helps!
3 0
4 years ago
Read 2 more answers
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
lions [1.4K]

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}

(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill

\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}

6 0
2 years ago
X+a=3/4 I don't know how to solve this and I need someone to help explain it to me.
Aneli [31]
I think you should Subtract
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8 0
3 years ago
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