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Kamila [148]
3 years ago
9

Find the product of-10/5 x (-15/5)

Mathematics
2 answers:
taurus [48]3 years ago
7 0

Answer:

6

Step-by-step explanation:

Equation: -\frac{10}{5}\cdot -\frac{15}{5}

1). Apply -a(-b)-ab: -\frac{10}{5}(-\frac{15}{5}=\frac{10}{5}\cdot \frac{15}{5}

2). \frac{10}{5} simplfies to 2, so 2\cdot \frac{15}{5}

3). 2\cdot 3

ikadub [295]3 years ago
6 0

Answer:

6

Step-by-step explanation:use math- way it will help you in future

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Well we know that
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So we can do r - c
(25x) - (6x + 15)

Now I gave you part of the answer. Can you simplify?
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I need an answer ASAP I will thank you and give you a like!
LenaWriter [7]

Answer:

Option C. As x approaches positive infinity, f(x) approaches positive infinity, and g(x) approaches negative infinity.

Step-by-step explanation:

we know that

Observing the table

The function f(x) is a increasing function

As the value of x increases, the value of f(x) increases

so

As x approaches positive infinity, f(x) approach positive infinity

<em>Find the slope of the linear equation g(x)</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the points (6, -2) and (3, 7)

substitute

m=\frac{7+2}{3-6}

m=\frac{9}{-3}=-3

The slope of the linear equation g(x) is negative

That means ----> Is a decreasing function

As the value of x increases, the value of g(x) decreases

so

As x approaches positive infinity, g(x) approach negative infinity

therefore

As x approaches positive infinity, f(x) approaches positive infinity, and g(x) approaches negative infinity.

6 0
3 years ago
Is the answer to 6x^2-x-15=0 x=5/3,-3/2 ? Using the quadratic formula
Nadya [2.5K]

Answer:

Hope it can help you...... Plz mark me as a brainlist..... Follow me....

4 0
3 years ago
Which of the relations given by the following sets of ordered pairs is a function?
adell [148]
Functions cannot have the same X value (the first number), but they can have the same Y value (the second number).
<span>A. {(1,2),(2,3),(3,4),(2,1),(1,0)}
B. {(2,−8),(6,4),(−3,9),(2,0),(−5,3)}
C. {(1,−3),(1,−1),(1,1),(1,3),(1,5)}
D. {(−2,5),(7,5),(−4,0),(3,1),(0,−6)}

Choice A. has two repeating X values [(1,2) and (1,0), (2,3) and (2,1)]
Choice B. has one repeating X value [(2, -8) and (2,0)]
Choice C. all has a repeating X value (1)
Choice D doesn't have any repeating X values.

In short, your answer would be choice D [</span><span>{(−2,5),(7,5),(−4,0),(3,1),(0,−6)}] because it does not have any repeating X values.</span>
8 0
4 years ago
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