Answer:
Step-by-step explanation:
(x^2 - 4)(x^2 - 4)
Simplifying
(x2 + -4)(x2 + -4)
Reorder the terms:
(-4 + x2)(x2 + -4)
Reorder the terms:
(-4 + x2)(-4 + x2)
Multiply (-4 + x2) * (-4 + x2)
(-4(-4 + x2) + x2(-4 + x2))
((-4 * -4 + x2 * -4) + x2(-4 + x2))
((16 + -4x2) + x2(-4 + x2))
(16 + -4x2 + (-4 * x2 + x2 * x2))
(16 + -4x2 + (-4x2 + x4))
Combine like terms: -4x2 + -4x2 = -8x2
(16 + -8x2 + x4)
For 3x + 12 + x, do like terms:
4x + 12
For 4(3 + x), multiply
12 + 4x
They are both the same, just written in different ways. One is adding like terms and the other is multiplying with parentheses. Even though it may be switched around, it is still the same.
Hope this helps :)
Answer:
m∠CEB is 55°
Step-by-step explanation:
Since ∠ADE = 55°, and ∠ADE is half of ∠ADC because ED bisects ∠ADC. Bisect means to cut in half.
∠ADC = 110° because it is double of ∠ADE.
Since AB║CD and AD║BC, the two sets of parallel lines means this shape is a parallelogram. In parallelograms, <u>opposite angles have equal measures</u>.
∠ADC = ∠CBE = 110°
All quadrilaterals have a sum of angles 360°. Since ∠DCB = ∠BAD and we know two of these other angles are each 110°:
360° - 2(110°) = 2(∠DCB)
∠DCB = 140°/2
∠DCB = ∠BAD = 70°
∠DCB was bisected by EC, which makes each divided part half.
∠DCE = ∠BCE = (1/2)(∠DCB)
∠DCE = ∠BCE = (1/2)(70°)
∠DCE = ∠BCE = 35°
All triangles' angles sum to 180°.
In ΔBCE, ∠BCE = 35° and ∠CBE = 110°.
∠CEB = 180° - (∠BCE + ∠CBE)
∠CEB = 180° - (35° + 110°)
∠CEB = 55°
Therefore m∠CEB is 55°.
Answer:
$104
Step-by-step explanation:
$260 - 60% = $104
The <em><u>correct answer</u></em> is:
The union of two sets is a combination of all elements from both sets. The intersection of two sets, on the other hand, is a set of the elements common to both sets.
For instance, if we have the sets {1, 3, 5, 7, 9} and {3, 6, 9, 12, 15}, the union would be the combination of both:
{1, 3, 5, 6, 7, 9, 12, 15}
The intersection of the sets would be the common elements. The only elements that are in both sets are 3 and 9. This makes the intersection
{3, 9}
