Ask question

Ask question

All categories

Angelina_Jolie [31]

4 years ago

11

Can u tell me which one is the median in here??

1 answer:

ki77a [65]4 years ago

4 0

Answer:

-1

Step-by-step explanation:

To calculate the median, you select the middle number. So first, we must put the numbers in order

-23, -20, -16, -<u>1,</u> -1, 10, 10

The middle number is -1. (there are 3 numbers either side)

You might be interested in

Hellllllllllpppppppppp pliz

LenaWriter [7]

The answer is C. I just divided the pages read by the time it took to read it.

For example: Fiona read 45 pages in 3 hours. 45 divided by 3 equals 15. Then, Albert read 30 pages in 6 hours. 30 divided by 6 equals 5.

8 0

3 years ago

How is the area of a sail related to the weight of the pilot on a hang glider?

Lisa [10]

The <u>correct answer</u> is:

The larger the surface area of the sail, the heavier the pilot can be and safely use the glider.

Explanation:

A hang glider must be able to support the weight of the pilot. The air pushing up under the sail (wing) of the glider helps support the weight. The more sail (wing) that you have, the more air pushing up, and the more weight it can hold.

3 0

3 years ago

Read 2 more answers

What is 5,000,000,000 times 17

Serggg [28]

Answer: 85000000000

Step-by-step explanation:

That’s a LOT Of ZeRoSsss

8 0

3 years ago

Read 2 more answers

Solve the triangle. Round your answers to the nearest tenth.

mixas84 [53]

Answer:

Angles: $\angle A = 43^{\circ}$ $\angle B = 55^{\circ}$ $\angle C = 82^{\circ}$

Sides: $BC = 20$ $AB = 29$ $AC =24$

Step-by-step explanation:

See attachment for complete question

From the attachment, we have:

$AB = 29$

$AC =24$

$\angle C = 82^{\circ}$

Required

Complete the missing side and missing angles

To calculate angle B, we apply sine laws:

$\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}$

In this case:

$\frac{AB}{sinC}=\frac{AC}{sinB}$

This gives:

$\frac{29}{sin(82^{\circ})}=\frac{24}{sinB}$

$\frac{29}{0.9903}=\frac{24}{sinB}$

Cross Multiply

$sinB * 29 = 24 * 0.9903$

Divide both sides by 29

$sinB = \frac{24 * 0.9903}{29}$

$sinB = 0.8196$

Take arcsin of both sides

$B = sin^{-1}(0.8196)$

$B = 55^{\circ}$

So:

$\angle B = 55^{\circ}$

To solve for the third angle, we make use of:

$\angle A + \angle B + \angle C = 180^{\circ}$

This gives:

$\angle A + 55^{\circ} + 82^{\circ} = 180^{\circ}$

$\angle A + 137^{\circ}= 180^{\circ}$

$\angle A = 180^{\circ}- 137^{\circ}$

$\angle A = 43^{\circ}$

Hence, the angles are:

$\angle A = 43^{\circ}$ $\angle B = 55^{\circ}$ $\angle C = 82^{\circ}$

To calculate the length of the third side, we apply cosine law

$BC^2 = AB^2 + AC^2 - 2*AB*AC*cosA$

$BC^2 = 29^2 + 24^2 - 2*29*24*cos(43^{\circ})$

$BC^2 = 841+ 576 - 1392*cos(43^{\circ})$

$BC^2 = 841+ 576 - 1392*0.7314$

$BC^2 = 841+ 576 - 1018.11$

$BC^2 = 398.89$

Take the square root of both sides

$BC = \sqrt{398.89$

$BC = 19.9722307217$

$BC = 20$

5 0

3 years ago

Half a number deacreased by 8 is -3

ra1l [238]

Answer:

5

Step-by-step explanation:

5 0

3 years ago