<em>Last year the chess club had 30 members. This year the club has 24 members. </em>
Last year, the chess club had 30 members. This year, the club has 24 members. Since this year had less than last year ( 30 > 24), the percent will be decreasing.
To find the percent decrease, you have to use the following formula.

Difference refers to the difference between the two numbers, 24 and 30. The difference between 24 and 30 is 6. Original refers to the original number, which is last year's amount of members in the chess group. Therefore, original = 30.
Substitute the numbers into the formula.

To convert the decimal to a fraction, multiply the decimal by 100.

The answer is the number of chess members decreased by 20%.
____
Since I started off by identifying whether it was decreasing or increasing, I did the work a bit differently. When finding the difference, you would usually subtract 30 from 24, which results in -6. Above I used 6, but if you used -6, you would end up with a result of -20%, which means it decreased by 20%. They bot end up with the same result, but you don't always have to first identify whether it's decreasing or increasing.
____
A. x-6=6
if u plug in 12, you get 12-6=6 which is true
all the other ones would be false if you plugged in 12
Answer:
conversion factor
Step-by-step explanation:
that is what I found on the internet
hope it helps :)
Answer:
-12, or 1 (see explanation)
Step-by-step explanation:
(-3)(+4)
Is the same as
4 * (-3)
which is
-12
Unless your problem is:
(-3) + 4
Then it is the same as
4 - 3
which is
1
Answer: the answer to your question is 36.25