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babymother [125]
3 years ago
9

Which expression is equivalent.

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0

Answer:

ok so the correct answer is A!

Step-by-step explanation:

hope it helped!

have a nice day.

kotykmax [81]3 years ago
3 0

Option A is the correct answer

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I need to pass so yk help​
Airida [17]

Answer:

(2)

Step-by-step explanation:

-3,2

-1,-1

y = ax + b \\ 2 =  - 3a + b \\  - 1 =  - a + b \\ 3 =  - 2a \\ a =  - 1.5

slope is -1.5

3 0
3 years ago
Helpppppppppp me plzzzzzzzzzz WILL MARK BRAINLIST if right
Dvinal [7]

Step-by-step explanation:

j=-m+g that's it I just get it

6 0
3 years ago
1. Mr. Jackson buys a pair of shoes for $41.12. He<br> hands the clerk a $50 bill.
Arlecino [84]

Answer:

Mr Jackson should get $8.88 back.

Step-by-step explanation:

$50 - $41.12 = $8.88

7 0
3 years ago
Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15
ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

a_{n+1} = ra_{n}

In which r is the common ratio.

This can be expanded for the nth term in the following way:

a_{n} = a_{1}r^{n-1}

In which a_{1} is the first term.

Or even:

a_{n} = a_{m}r^{n-m}

The sum of the first n terms of a geometric sequence is given by:

S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}

Finding the common ratio:

a_{3} = 3.645, a_{8} = 15

a_{n} = a_{m}r^{n-m}

a_{8} = a_{3}r^{8-3}

a_{3}r^{5} = a_{8}

3.645r^{5} = 15

r^{5} = \frac{15}{3.645}

r = \sqrt[5]{\frac{15}{3.645}}

r = 1.327

Finding the first term:

a_{3} = a_{1}r^{2}

a_{1} = \frac{a_{3}}{r^{2}}

a_{1} = \frac{3.645}{(1.327)^{2}}

a_{1} = 2.07

Sum of the first nine terms:

S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44

The sum of the first nine terms of the sequence is 74.44.

8 0
3 years ago
Read 2 more answers
A group issimpleif it has no nontrivial proper normal subgroups. LetGbe a simple group of order168. How many elements of order 7
stepladder [879]

Answer:

6*8=48 groups with elements of order 7

Step-by-step explanation:

For this case the first step is discompose the number 168 in factors like this:

168 = 8*3*7= 2^3 *3*7

And for this case we can use the Sylow theorems, given by:

Let G a group of order p^{\alpha} m  where p is a prime number, with m\leq 1 and p not divide m then:

1) Syl (G) \neq \emptyset

2) All sylow p subgroups are conjugate in G

3) Any p subgroup of G is contained in a Sylow p subgroup

4) n(G) =1 mod p

Using these theorems we can see that 7 = 1 (mod7)

By the theorem we can't have on one Sylow 7 subgroup so then we need to have 8 of them.

Every each 2 subgroups intersect in a subgroup with a order that divides 7. And analyzing the intersection we can see that we can have 6 of these subgroups.

So then based on the information we can have 6*8=48 groups with elements of order 7 in G of size 168

3 0
3 years ago
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