4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2
5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3
6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1
The x in your equation is 16/5 or 3 1/5 or 3.2 if you want it simplified
Answer:
The second answer, and possibly the first answer as also true.
She did run a test that would indicate its an unbalanced dice, but this wasn't tried out with a different person throwing the dice.
Step-by-step explanation:
This is because from the computer generator results we see 11 of the 25 values are estimating at 1/5 when we know dice are 1/6 and more than 1/2 show just under 1/5 which balances this to be 1/6
But there are 9/25 tests that showed values under 10 throws found a 6 in 9/25 events = 1/3 approx out of 1/10 of the throws, and 1/3 is still a higher value than 1/6 of the multiple throws so indicates 100 throws would not be enough to tell as we cannot possibly assume her results are comparable with a computer generator.As the computer generator completed 25 x 100 throws and have just compared only x10 in relation to 1/10 of the events of the generated computer. This showing 9 of the 25 (100) throw events in relation scores 1/3 of the results a 6. The answer is she would need to throw somewhere between 1000 and 3000 to compare to the computers results.
3:4
32:32 to begin with
24:32, which can be simplified by dividing both sides by 8.
