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Korvikt [17]
3 years ago
7

An average ant is 1/4 inch long. An average aphid is 3/32 inch long.how many times longer is an average ant that an average aphi

d. Please put in simplest form
Mathematics
2 answers:
belka [17]3 years ago
8 0

Answer:

An average ant is 2\frac{2}{3} times longer than an average aphid

Step-by-step explanation:

Let

x------> an average ant long

y-----> an average aphid long

we have

x=\frac{1}{4}\ in

y=\frac{3}{32}\ in

we know that

\frac{x}{y}=\frac{(1/4)}{(3/32)}=\frac{32}{12}=\frac{8}{3}

convert to mixed number

\frac{8}{3}=\frac{6}{3}+\frac{2}{3}=2+\frac{2}{3}=2\frac{2}{3}

therefore

\frac{x}{y}=2\frac{2}{3}

isolate the variable x

x=2\frac{2}{3}y


Aleks [24]3 years ago
5 0
This  is a proportion which can be obtained just dividing the sizes;

(1/4) / (3/32) = 8/3 ≈ 2.7 times larger
You might be interested in
Hallar la ecuación de la recta que pasa por los puntos A(1,3) y B(3,7). Representarla gráficamente. Indicar su pendiente.
Fynjy0 [20]

Answer:

<h2>A</h2>

Step-by-step explanation:

la recta:

y-yo=m(x-xo) (*)

P=(xo,yo)

m=\frac{Ya-Yb}{Xa-Xb}

substituindo:

m=\frac{3-7}{1-3}\\\\m=2

Seja P=A=(xo=1,yo=3), utilizando a formula (*)

y-3=2(x-1)\\y=2x-2+3\\y=2x+1

3 0
2 years ago
4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B
AleksAgata [21]

Answer:

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

Step-by-step explanation:

1) Data given and notation  

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

\hat p=\frac{63}{200}=0.315 estimated proportion of lawyers had used some form of advertising for their business

p_o=0.25 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

8 0
3 years ago
Answer fast please!
zepelin [54]
I believe it's A but it's not exactly clear
6 0
3 years ago
Read 2 more answers
Patulong naman po need kona po ngayun to
Leno4ka [110]

1.d

2.d

hope it helps

...............

3 0
2 years ago
Read 2 more answers
The divison of the whole bumber N by 13 gives a quotient of 15 and a remainder of 12. Find N
Soloha48 [4]
N/13 = 15 with a remainder of 12:

Multiply both sides of this eq'n by 13, to eliminate fractions:

15N = 13(15) + 12 = 195 + 12 = 207


Let's check our answer.

 Divide 13 into 207.  Using a calculator, we find the quotient is 15.923.

The remainder is 0.923 times 13, or 12.  

The number N is 207
7 0
3 years ago
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