Question

find an equation for the line that is perpendicular to the graph of 5x-3y=9 if the two lines intersect at x=30

Answer 1

Answer:

$y-47 = -\frac{3}{5}(x-30)$

in Point Slope Form

Step-by-step explanation:

The line 5x - 3y = 9 converts to slope intercept form as y = 5/3 x-3. When x = 30, it has the value y = 5/3(30) - 3 = 50 - 3 = 47. SO it has the point (30,47).

This line has a slope of 5/3. The line perpendicular to it will have the negative reciprocal slope -3/5. Using this slope and the point (30,47), we write the ine in point slope form:

$y-y_1=m(x-x_1)\\y-47 = -\frac{3}{5}(x-30)$