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3 years ago

15

find an equation for the line that is perpendicular to the graph of 5x-3y=9 if the two lines intersect at x=30

1 answer:

vlabodo [156]3 years ago

4 0

Answer:

$y-47 = -\frac{3}{5}(x-30)$

in Point Slope Form

Step-by-step explanation:

The line 5x - 3y = 9 converts to slope intercept form as y = 5/3 x-3. When x = 30, it has the value y = 5/3(30) - 3 = 50 - 3 = 47. SO it has the point (30,47).

This line has a slope of 5/3. The line perpendicular to it will have the negative reciprocal slope -3/5. Using this slope and the point (30,47), we write the ine in point slope form:

$y-y_1=m(x-x_1)\\y-47 = -\frac{3}{5}(x-30)$

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Step-by-step explanation:

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150 + 35x

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60 × x months = 60x

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3 years ago

Luis hizo un viaje en el coche en el cual consumio 20 l de gasolina. el trayecto lo hizo en dos etapas en la primera consumio 2/

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Answer: $24\ liters$

Step-by-step explanation:

Let be "x" the amount of gasoline in liters that the car's tank had at the beginning of the trip.

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$\frac{2}{3}x$

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$x-\frac{2}{3}x=\frac{1}{3}x$

3. In the second part of the trip the car used $\frac{1}{2}$ of the remaining. This is:

$(\frac{1}{3}x)(\frac{1}{2})=\frac{1}{6}x$

4. The total amount ot gasoline used in this trip was 20 liters.

5. Then, with this information, you can write the following equation:

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6. Finally, you must solve for "x" in order to find its value. This is:

$\frac{2}{3}x+\frac{1}{6}x=20\\\\\frac{5}{6}x=20\\\\5x=120\\\\x=24$

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3 years ago