What is the sum of the lengths of the shortest and longest ski trails? pls help with number 5
2 answers:
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Answer:
3rd option
Step-by-step explanation:
Since the centre of dilatation is at the origin then multiply the coordinates by
K (- 3, 9 ) → K' (- 3( ), 9(
) ) → K' (- 1, 3 )
L (- 9, 0 ) → L' (- 9( ), 0 (
) ) → L' (- 3, 0 )
M (2, - 8 ) → M' (2 ( ), - 8 (
) ) → M' (
, -
)
N (6, 4 ) → N' (6 ( ) , 4 (
) ) → N' ( 2,
)
Change the function into vertex form:
f(x)=x²-10x+16
make a square by (adding half of -10)², which is 25, then subtract it:
f(x)=x²-10x+25-25+16
f(x)=(x-5)²-9
so the vertex is at (5,-9)
another way to do it:
f(x)=x²-10x+16
the vertex is when x=-
, b=-10, a=1 in this case.
x=-(-10/2*1)=5
plug x=5 into the quadratic function, you get f(x)=-9
f(x)=x²-10x+16
make a square by (adding half of -10)², which is 25, then subtract it:
f(x)=x²-10x+25-25+16
f(x)=(x-5)²-9
so the vertex is at (5,-9)
another way to do it:
f(x)=x²-10x+16
the vertex is when x=-
x=-(-10/2*1)=5
plug x=5 into the quadratic function, you get f(x)=-9