I’m assuming you just substitute 2 in the equation for x:
4 + x = 4 + 2 = 6
Answer = 6
The answer is the first choice.
P(both even) = (4P1)(3P1) / 9P2
One way you could do this is by dividing 94 by 3 and then 95 by 4. This gives you the KPH (Kilometers per hour) of both trains. The first speed you mentioned, we will call that speed 'A.' The second one will be speed 'B.' Speed A's KPH is 23.75 MPH. Speed B's KPH is 31.333. We can change these into fractions (23 3/4 and 31 1/3.) These fractions could then be set into like terms. (This gives us 285/12 and 376/12) We then add these together. This gives us 661/12. The next thing to do is to convert this back to a decimal form, which gives us 55.0833.... Divide this number by two, and that is your answer. The average speed of the train is 29.04 KPH (This number is rounded to the nearest hundreth- be sure to make a note of that on your answer sheet)
