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2 years ago

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Mathematics

1 answer:

Aneli [31]2 years ago

6 0

The answer is A

point c is 5 units to the left and 3 units up when across the y-axis

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PLEASE HELP ME GUYS OR I WONT PASS this calculus!!!!

KonstantinChe [14]

Answer:

b. $\displaystyle \frac{1}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle H(x) = \sqrt[3]{F(x)}$

Step 2: Differentiate

Rewrite function [Exponential Rule - Root Rewrite]: $\displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}$
Chain Rule: $\displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]$
Basic Power Rule: $\displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)$
Simplify: $\displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}$

Step 3: Evaluate

Substitute in x [Derivative]: $\displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}$
Substitute in function values: $\displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}$
Exponents: $\displaystyle H'(5) = \frac{6}{3(4)}$
Multiply: $\displaystyle H'(5) = \frac{6}{12}$
Simplify: $\displaystyle H'(5) = \frac{1}{2}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0

2 years ago

Add -13/4+2/5 using the number line. select the location on the number line to plot the sum

Ivahew [28]

The answer is if you convert. we cant see the number line so, we cant tell you the second part of the problem.. attach the image please.

ok so convert.. -13/4 becomes -65/20 and 2/5 becomes 8/20, so add that and get -57/20, then simplify how you want to. thats your answer

4 0

3 years ago

Ares of a rectangular floor of your house is Ax+5x-2. if the length is x+2 units, find A

Snezhnost [94]

Answer:

A=4.

Step-by-step explanation:

Note: In the expression of area the first term should be $Ax^2$ .

It is given that area of a rectangular floor of your house is $Ax^2+5x-2$ and the length is $(x+2)$ units.

We know that, area of a rectangle is

$Area=length\times width$

Since length of the rectangle is $(x+2)$ , therefore $(x+2)$ is a factor of $Ax^2+5x-2$ and the value of $Ax^2+5x-2$ is 0 at x=-2.

$A(-2)^2+5(-2)-2=0$

$4A-10-2=0$

$4A-12=0$

$4A=12$

Divide both sides by 4.

$A=4$

Therefore, the value of A is 4.

7 0

2 years ago

For which function is the domain -6 is less than or equal to x less than or equal to -1 not appropriate? A) y=x^2 B) y=2x C) y=

elena-s [515]

Answer: idk jus needed the points so im answering

3 0

2 years ago

Gaveing out points for helpers!!

Alekssandra [29.7K]

Because the two angles add up to equal 90, you would make an equation set to equal 90. On the other end you add the measures of your angles together because they are adding up to equal 90. This would look like 2x+5+35=90 and you solve from here. Add like terms making it 2x+40=90 then you subtract 40 from both sides making it 2x=50 and then divide by 2 on both sides which leaves you with x=25.

3 0

2 years ago