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Fittoniya [83]
3 years ago
12

Solve the following quadratic equation: (x-16)^2= 256

Mathematics
1 answer:
fiasKO [112]3 years ago
7 0
Simplifying
(x + -16) * 2 = 256

Reorder the terms:
(-16 + x) * 2 = 256

Reorder the terms for easier multiplication:
2(-16 + x) = 256
(-16 * 2 + x * 2) = 256
(-32 + 2x) = 256

Solving
-32 + 2x = 256

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + 2x = 256 + 32

Combine like terms: -32 + 32 = 0
0 + 2x = 256 + 32
2x = 256 + 32

Combine like terms: 256 + 32 = 288
2x = 288

Divide each side by '2'.
x = 144

Simplifying
x = 144
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Answer:

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Step-by-step explanation:

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valentinak56 [21]

Answer:

The general limit exists at <em>x</em> = 9 and is equal to 300.

Step-by-step explanation:

We want to find the general limit of the function:

\displaystyle \lim_{x \to 9}(x^2+2^7+(9.1\times 10))

By definition, a general limit exists at a point if the two one-sided limits exist and are equivalent to each other.

So, let's find each one-sided limit: the left-hand side and the right-hand side.

The left-hand limit is given by:

<h3>\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))</h3>

Since the given function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

300

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\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))=300

The right-hand limit is given by:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))

Again, since the function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

=300

Therefore:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Thus, we can see that:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1\times 10))=\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Since the two-sided limits exist and are equivalent, the general limit of the function does exist at <em>x</em> = 9 and is equal to 300.

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0.250

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