Answer:
Never
Never
Never
Step-by-step explanation:
The equations given are
2x1−6x2−4x3 = 6 ....... (1)
−x1+ax2+4x3 = −1 ........(2)
2x1−5x2−2x3 = 9 ..........(3)
the values of a for which the system of linear equations has no solutions
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.
a unique solution,
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
The value of a = never
infinitely many solutions.
Divide equation 1 by 2 we will get
X1 - 3X2 - 2X3 =3
Add the above equation with equation 3. This will result to
3X1 - 8X2 - 4X3 = 12
Everything ought to be the same. Since they're not.
Value of a = never.
Answer:
Michael's present age = p + 5
Michael's present age = 3p + 15
Sum of there ages 6 year age = 5p + 38
Sum of there ages 3 year ago = 5p - 11
Step-by-step explanation:
Assume;
Age of Rui Feng = x
Age of Micheal = x + 5
Age if Vishal = 3[x+5]
Given:
Age of Rui Feng = P
Computation:
Michael's present age = Age of Rui Feng + 5
Michael's present age = p + 5
Vishal's present age = 3[p + 5]
Michael's present age = 3p + 15
Sum of there ages 6 year age = [p + 6] + [p + 5 + 6] + 3[p + 5] + 6
Sum of there ages 6 year age = 5p + 38
Sum of there ages 3 year ago = [p - 3] + [p + 5 - 3] + 3[p + 5] - 3
Sum of there ages 3 year ago = 5p - 11
A(n)=a(1)+d(n-1), d=a(16)-a(15)=-5-(-53)=48
a(15)=a(1)+d*(15-1),
-53=a(1)+48*(15-1),
a(1)=-53-48*14= -725
a(n)=-725+48(n-1)