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scZoUnD [109]
3 years ago
5

Help fill in the blanks no

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

Here is the full proof:

AC bisects ∠BCD      Given

∠CAB ≅ ∠CAD          Definition of angle bisector

DC ⊥ AD                    Given

∠ADC = 90°               Definition of perpendicular lines

BC ⊥ AB                    Given

∠ABC = 90°               Definition of perpendicular lines

∠ADC ≅ ∠ABC          Right angles are congruent

AC = AC                     Reflexive property

ΔCAB ≅ ΔCAD          SAA

BC = DC                     CPCTC          

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3 years ago
Find the midpoint of side EF. (4 points)
umka2103 [35]

Answer:

Midpoint of side EF would be (-.5,4.5)

Step-by-step explanation:

We know that the coordinates of a mid-point C(e,f) of a line segment AB with vertices A(a,b) and B(c,d) is given by:

e=a+c/2,f=b+d/2

Here we have to find the mid-point of side EF.

E(-2,3) i.e. (a,b)=(2,3)

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Hence, the coordinate of midpoint of EF is:

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2 years ago
On a graph, the solution to a system of linear equations is represented by __________.
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4 0
3 years ago
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Need to write steps and solve <br> thanks
nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}

As per the formula,  \frac{x_{1}+x_{2}}{2}=5, \frac{y_{1}+y_{2}}{2}=-11

Here x_{1}=3; y_{1}=5

Substituting the value of x_{1} we get,

\frac{3+x_{2}}{2}=5

3+x_{2}=5\times2

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x_{2}=7

Substituting the value of x_{2} we get,

\frac{5+y_{2}}{2}=-11

5+y_{2}=-11\times2

y_{2}=-22-5

y_{2}=-27

So, the coordinates of V is (7,-27)

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3 years ago
What is 100 divided by 456
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It's 4 with a remainder of 56 
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3 years ago
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