Answer:
Correct answer is A.
The higher the enzyme, the higher the Vmax
Explanation:
Although, in the absence of enzyme, the rate of a reaction(Vmax) increase linearly with substrate concentration. The reaction rate is given as dp/dt.
The rate of a reaction involving enzyme also increases.
At low enzyme concentrations or high substrate concentrations, all of the available enzyme active sites could be occupied with substrates. Therefore, increasing the substrate concentration further will not change the rate of diffusion. In other words, there is some maximum reaction rate (Vmax) when all enzyme active sites are occupied. The reaction rate will increase with increasing substrate concentration, but must asymptotically approach the saturation rate, Vmax. Vmax is directly proportional to the total enzyme concentration, E
Answer:
The work done by the weightlifter, W = 700 J
The power of the weightlifter, P = 350 watts
Explanation:
A weightlifter lifts a set of weights a vertical distance, s = 2 m
The force exerted to lift the weight, F = 350 N
The work done by the body is defined as the product of the force applied by the body to the displacement it caused.
W = F x s
= 350 N x 2 m
= 700 J
The work done by the weightlifter, W = 700 J
The time taken by the weightlifter to lift the weight, t = 2 s
The power is defined as the rate of body to do work. It is given by the equation,
P = W / t
= 700 J / 2 s
= 350 watts
Hence, the power of the weightlifter, P = 350 watts
Answer:
twice the original speed
Explanation:
the centripetal force is the force of an object moving in a circle of turning and it is given by the expression
where f = force of the object
m = mass
v = velocity
r = radius of the circle
first we need to know what the orignal speed will be then we can tell what will happen if the radius of the circle is changed to 4R.
from the expression for the centripetal force, we need to make the velocity subject of the formula
now, if the radius is changed to 4R
in the expression for v above i will need to just insert 4R in place of r
the square root of 4 is 2,
therefore
we can see that this is just twice of what the original speed was.
Answer:
3.75 m/s
Explanation:
Given that a bumblebee is flying to the right when a breeze causes the bee to slow down with a constant leftward acceleration of magnitude 0.50 m/s^2. After 2.0 s the bee is moving to the right with a speed of 2.75 m/ s
What was the velocity of the bumblebee right before the breeze?
Since the breeze blows with the acceleration of 0.5 m/s^2 for 2 seconds, we can calculate the magnitude of the velocity at which it moves.
Acceleration = velocity/ time
Substitute the acceleration and time into the formula
0.5 = V/2
Cross multiply
V = 2 × 0.5
V = 1 m/s
The bumblebee is travelling right ward while the wind travels leftward.
The relative velocity = 2.75 m/s
Let the bumblebee speed = Vb
While the wind = VW
Vb - Vw = 2.75
Substitute the wind speed into the formula
Vb - 1 = 2.75
Vb = 2.75 + 1
Vb = 3.75 m/s
Therefore, the velocity of the bumblebee right before the breeze is 3.75 m/s
