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lord [1]
3 years ago
5

Which of the followings are true about Vmax? A. The higher the [enzyme], the higher the Vmax B. Vmax is proportional to k2 C. Vm

ax is proportional to km D. Vmax is proportional to k1
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0

Answer:

Correct answer is A.

The higher the enzyme, the higher the Vmax

Explanation:

Although, in the absence of enzyme, the rate of a reaction(Vmax) increase linearly with substrate concentration. The reaction rate is given as dp/dt.

The rate of a reaction involving enzyme also increases.

At low enzyme concentrations or high substrate concentrations, all of the available enzyme active sites could be occupied with substrates. Therefore, increasing the substrate concentration further will not change the rate of diffusion. In other words, there is some maximum reaction rate (Vmax) when all enzyme active sites are occupied. The reaction rate will increase with increasing substrate concentration, but must asymptotically approach the saturation rate, Vmax. Vmax is directly proportional to the total enzyme concentration, E

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This type of polarization occurs when light strikes the atoms of a material.
zloy xaker [14]

Option C i.e scattering is the correct answer.

Scattering type of Polarization occurs when light strikes the atoms of a material.

Polarization is the process of transforming unpolarized light into polarized light. There are four methods of polarisation--Transmission, Refraction, Reflaction and Scattering.

4 0
3 years ago
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The magnification produced by a plane mirror is +1. what does this mean?
disa [49]

Answer:

The magnification produced by a plane mirror is +1

means then the size of the image is equal to the size of the object. If m has a magnitude greater than 1 the image is larger than the object, and an m with a magnitude less than 1 means the image is smaller than the object.

6 0
3 years ago
The atlas stone’s is a strong man competition where athletes have to load 5 stones of masses 100kg, 120kg, 140kg, 160kg and 180k
lyudmila [28]

Answer: 6250 joules

Explanation:

The work needed to lift an object of mass M by a height H is equal to:

w = M*g*H

where h = 10m/s^2

then the total work that he did is equal to the sum of the work for every stone:

W = (100kg*g*H) + (120kg*g*H) + (140kg*g*H) + (160kg*g*H) + (180kg*g*H)

 = (100kg + 120kg + 140kg + 160kg + 180kg)*g*H

= (500kg)*g*H

and now we can repalce g by 10m/s^2 and H by 125cm

But you can notice that we have two different units of distance, so knowing that 100cm = 1m

we can write H =  125cm = (125/100) m = 1.25 m

Then we have:

H = 500kg*10m/s^2*1.25m = 6250 J

3 0
3 years ago
Masses A and B rest on very light pistons that enclose a fluid.There is no friction between the pistons and the cylinders they f
RSB [31]

Answer:

D)Not enough information

Explanation:

According to Pascal's principle, the pressure exerted on the two pistons is equal:

p_A = p_B

Pressure is given by the ratio between force F and area A, so we can write

\frac{F_A}{A_A}=\frac{F_B}{A_B}

The force exerted on each piston is just equal to the weight of the corresponding mass: F=W=mg, where m is the mass and g is the gravitational acceleration. So the equation becomes

\frac{m_A g}{A_A}=\frac{m_B g}{A_B}

Now we can rewrite the mass as the product of volume, V, times density, d:

\frac{V_A d_A g}{A_A}=\frac{V_B d_B g}{A_B}

We also know that A_B = 2.0 m^2\\A_A = 1.0 m^2

So we can further re-arrange the equation (and simplify g as well):

\frac{V_A d_A}{1}=\frac{V_B d_B}{2}

\frac{d_A}{d_B}=\frac{V_B}{2V_A}

We are also told that block B has bigger volume than block A: V_B > V_A. However, this information is not enough to allow us to say if the fraction on the right is greater than 1 or smaller than 1: therefore, we cannot conclude anything about the densities of the two objects.

3 0
3 years ago
An inductor is connected to a 26.5 Hz power supply that produces a 41.2 V rms voltage. What minimum inductance is needed to keep
alexira [117]

Answer:

The minimum inductance needed is 2.78 H

Explanation:

Given;

frequency of the AC, f = 26.5 Hz

the root mean square voltage in the circuit, V_{rms} = 41.2 V

the maximum current in the circuit, I₀ = 126 mA

The root mean square current is given by;

I_{rms} = \frac{I_o}{\sqrt{2} } \\\\I_{rms}  = \frac{126*10^{-3}}{\sqrt{2} }\\\\I_{rms}  =0.0891 \ A

The inductive reactance is given by;

X_l = \frac{V_{rms}}{I_{rms}} \\\\X_l= \frac{41.2}{0.0891}\\\\X_l = 462.4 \ ohms

The minimum inductance needed is given by;

X_l = \omega L\\\\X_l = 2\pi  fL\\\\L = \frac{X_l}{2\pi f}\\\\L = \frac{462.4}{2\pi *26.5}\\\\L = 2.78 \ H

Therefore, the minimum inductance needed is 2.78 H

7 0
3 years ago
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