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klemol [59]
4 years ago
11

Observing a phenomenon in the lab includes which of the following?

Chemistry
1 answer:
dedylja [7]4 years ago
8 0

Answer:

D

Explanation:

Identifying unique features of evidence

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WHAT MASS OF WATER WILL BE PRODUCED FROM 2.70 MOLES OF CA(OH)2 REACTING WITH HCI
Keith_Richards [23]

<u>Answer:</u> The mass of water produced in the reaction is 97.2 grams

<u>Explanation:</u>

We are given:

Moles of calcium hydroxide = 2.70 moles

The chemical equation for the reaction of calcium hydroxide and HCl follows:

Ca(OH)_2+HCl\rightarrow CaCl_2+2H_2O

By Stoichiometry of the reaction:

1 mole of calcium hydroxide produces 2 moles of water

So, 2.70 moles of calcium hydroxide will produce = \frac{2}{1}\times 2.70=5.40mol of HCl

To calculate mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of water = 18 g/mol

Moles of water = 5.40 moles

Putting values in above equation, we get:

5.40mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(5.40mol\times 18g/mol)=97.2g

Hence, the mass of water produced in the reaction is 97.2 grams

3 0
4 years ago
Pb(CH3COO)2 + H2S --&gt; PbS + CH3COOH 1. How many moles are produced of PbS when 5.00 grams of Pb(CH3COO)2 is reacted with H2S?
shutvik [7]

Answer:

1. 0.0154mole of PbS

2. Double displacement reaction

Explanation:

First, let write a balanced equation for the reaction. This is illustrated below:

Pb(CH3COO)2 + H2S —> PbS + 2 CH3COOH

Molar Mass of Pb(CH3COO)2 = 207 + 2(12 + 3 + 12 + 16 +16) = 207 + 2(59) = 207 + 118 = 325g

Mass of Pb(CH3COO)2 = 5g

Number of mole = Mass /Molar Mass

Number of mole of Pb(CH3COO)2 = 5/325 = 0.0154mole

From the equation,

1mole of Pb(CH3COO)2 produced 1mole of PbS.

Therefore, 0.0154mole of Pb(CH3COO)2 will also produce 0.0154mole of PbS

2. The name of the reaction is double displacement reaction since the ions in the two reactants interchange to form two different products

5 0
3 years ago
How many grams of carbon dioxide will be produced if 76.4 grams of
goldfiish [28.3K]

Answer:

Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556 moles of C2H3Br3 are required. Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent.

Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: A. 76.4g &times; (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g &times; (1 mole/ 32 g) = 1.53 moles O2 B.

Explanation:

MRK ME BRAINLIEST PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Map%3A_Introductory_Chemistry_(Tro)/08%3A_Quantities_in_Chemical_Reactions/8.04%3A_Limiting_Reactant_and_Theoretical_Yield

5 0
3 years ago
**EASY**
Svetach [21]
Answer: But because part 2 stays the same
3 0
3 years ago
How many nadh molecules are made from one molecule of acetyl coa going through the krebs cycle?
Mashcka [7]

Answer:

3 NADH molecules are made from each molecule of acetyl CoA through the Krebs Cycle.

Explanation:

First, 1 NADH is produced from each carbon lost from the 6-carbon citric acid (2 NADH total). Lastly, 1 additional NADH is made from the transformation of malate into oxaloacetic acid (acceptor molecule for acetyl CoA).

5 0
2 years ago
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