35.46 g silver nitrate reacts with 52.61 g sodium chloride to produce silver chloride and sodium nitrate.
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To help you answer this question, you can search a sample reaction in the internet for hydroboration-oxidation. Take a look at the attached picture. The sample reaction is shown at the top. We can deduce that the original compound must be an alkene. Following the pattern, compound a must be 2-methylbutene as shown in the picture.
