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prisoha [69]
3 years ago
13

How many moles are in 1.80g of N2?​

Chemistry
2 answers:
jeka57 [31]3 years ago
7 0

Answer:

28.0134

Explanation:

Dafna1 [17]3 years ago
6 0

Answer:

Explanation:

n=m/Mr

Molar mass =2(14)

n=1.80/28

n= 0.064

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The table below shows the volume of two samples, A and B, when placed in three containers of different volumes.
deff fn [24]

Answer: B is a gas because its volume is less than the volume of the containers.

Explanation: hope this help bye

7 0
2 years ago
Read 2 more answers
stbank, Question 075 Get help answering Molecular Drawing questions. Compound A, C6H12 reacts with HBr/ROOR to give compound B,
Law Incorporation [45]

Answer:

Explanation:

In this case we want to know the structures of A (C6H12), B (C6H13Br) and C (C6H14).

A and C reacts with two differents reagents and conditions, however both of them gives the same product.

Let's analyze each reaction.

First, C6H12 has the general formula of an alkene or cycloalkane. However, when we look at the reagents, which are HBr in ROOR, and the final product, we can see that this is an adition reaction where the H and Br were added to a molecule, therefore we can conclude that the initial reactant is an alkene. Now, what happens next? A is reacting with HBr. In general terms when we have an adition of a molecule to a reactant like HBr (Adding electrophyle and nucleophyle) this kind of reactions follows the markonikov's rule that states that the hydrogen will go to the carbon with more hydrogens, and the nucleophyle will go to the carbon with less hydrogen (Atom that can be stabilized with charge). But in this case, we have something else and is the use of the ROOR, this is a peroxide so, instead of follow the markonikov rule, it will do the opposite, the hydrogen to the more substituted carbon and the bromine to the carbon with more hydrogens. This is called the antimarkonikov rule. Picture attached show the possible structure for A. The alkene would have to be the 1-hexene.

Now in the second case we have C, reacting with bromine in light to give also B. C has the formula C6H14 which is the formula for an alkane and once again we are having an adition reaction. In this case, conditions are given to do an adition reaction in an alkane. bromine in presence of light promoves the adition of the bromine to the molecule of alkane. In this case it can go to the carbon with more hydrogen or less hydrogens, but it will prefer the carbon with more hydrogens. In this case would be the terminal hydrogens of the molecules. In this case, it will form product B again. the alkane here would be the hexane. See picture for structures.

8 0
3 years ago
..............................................
Vilka [71]
The period is the end of the sentence!!!
6 0
2 years ago
Atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron. giv
valina [46]

Answer:

Option A is correct.

Atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron

Explanation:

Atomic orbitals developed using quantum mechanics make use of quantum numbers.

There are four different quantum numbers that all work to give the region of space where a particular electron has the highest probability of being located.

The four quantum numbers that describes an electron's most likely location in an atom include

1) Principal quantum number, denoted by letter n. This quantum number gives the shell that an electron in an atom belongs to. It can take on natural number values from 1 (for the shell closest to the nucleus) through 2, 3, 4.... till rhe outermost shell.

2) Azimuthal/Angular Momentum quantum number, denoted by l. This quantum number describes the subshell or orbital within a shell that the electron belongs to in an atom.

It can take on values that can range from 0 to (n-1). These are the spdf orbitals with s-orbital having l-quantum number of 0, p-orbital with l-quantum number of 1 etc.

3) Magnetic quantum number, denoted by letter m. This describes the sub-orbital that the electron belongs to. It's values for electrons in a particular orbital vary from -l through 0 to +l.

E.g. orbital with l = 1 has electrons whose magnetic quantum number vary from -1, 0, +1.

orbital with l = 2 has electrons whose magnetic quantum number vary from -2, -1, 0, +1, +2.

4) Spin quantum number, denoted by letter s.

This describes the orientation of the electron's spin. Whether clockwise or anti-clockwise in it's sub-orbital. It can take on only values of (+1/2) or (-1/2).

So, these four quantum numbers, numbers that were made known because of quantum mechanics, show that atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron in an atom.

Hope this Helps!!!

5 0
3 years ago
If a sodium ion (Na+) has a positive charge and loses an electron when combined with chlorine, will the sodium atom become a new
Alina [70]

Answer:

No

Explanation:

loss of electron doesn't affect the element.

only change in proton number can, as we notice in nuclear chemistry.

please mark brainliest

7 0
3 years ago
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