Given:
A pilot can travel 450 miles with the wind in the same amount of time as 360 miles against the wind.
Pilot's speed in still air is 315 miles per hour.
To find:
The speed of the wind.
Solution:
Let the speed of wind be x miles per hour.
Speed with wind = 315+x miles per hour
Speed against wind = 315-x miles per hour
We know that,
According to the question,
Divide both sides by 90.
By cross multiplication, we get
Divide both sides by 9.
Therefore, the speed of wind is 35 miles per hour.
At the end of each year, the amount is (1 + 11%) = 1.11 times the amount at the beginning of the year. When that multiplier is applied 5 times, the result is
$30 * 1.11^5 ≈ $50.55
Answer:
The n th of the given sequence is
Step-by-step explanation:
<u>Step 1</u> :-
Given sequence is 20,14,8,2,.......this sequence in arithmetic progression but this sequence is decreasing sequence.
given first term is 20 and difference is
now the nth term of given sequence is
by using formula
final answer:-
<u>verification</u>:-
put n=1 we get first term is 20
put n=2 we get second term is 14
put n=3 we get third term is 8
put n=4 we get fourth term is 2
so the n th term of sequence is
Answer:
y = 3x - 4
Step-by-step explanation:
The line crosses the y-axis at -4. The line goes 3 down and 1 left.
Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Step-by-step explanation:
When population standard deviation is not given ,The confidence interval population proportion is given by ( ):-
, where n= Sample size.
s= Sample standard deviation
= sample mean
t* = Critical t-value (Two-tailed)
As per given , we have
n= 64
Degree of freedom : df = n-1=63
s= 5.5
Significance level :
Two-tailed T-value for df = 63 and would be
(By t-distribution table)
i.e. t*= 1.669
The 90% confidence interval for the population mean μ would be
∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,