Check the picture below.
how do we know? well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.
now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,
so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).
what does the solution mean? It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.
First find the area of the parallelogram
Area of parallelogram = b x h
= 12 x 7
= 84
Then find area of kite
Area of kite = (xy)/2
= (7 x 12)/2
= 84/2
= 42
Now we are gonna subtract the area of the kite from the area of the parallelogram.
84 - 42 = 42
Therefore the area of the shaded region is 42.
Note that 60 minutes is 1 standard deviation away from the mean and from recalling the 68-95-99.7 rule, the area that will remain is (100 - 68) = 32%. However, we only want the leftmost portion of this area, so the answer is 32%/2 = 16%.
<span>Choose D.</span>
Answer:
Step-by-step explanation:
Comment
You are given values for the adjacent side of <x and the hypotenuse of a right triangle. This defines the Cosine of an angle
Equation
Cos(x) = a/c the way you have labeled it.
Givens
a = 9
c = 18
Solution
Cos(x) = a / c
Cos(x) = 9 / 18
cos(x) = 1/2
x = cos-1(1/2)
x = 60 degrees
Answer
x = 60
