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3 years ago

11

Brianna makes $9.60 per hour. She worked 5 hours and 40 minutes on Saturday. On Sunday she worked for 1 hour and 10 minutes less

than she did on Saturday. How much money did Brianna make combined on Saturday and Sunday?

1 answer:

valentina_108 [34]3 years ago

3 0

She made 69.31 bucks

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An advertiser goes to a printer and is charged $73 for 100 copies of one flyer and $82 for 400 copies of a similar flyer. Assumi

USPshnik [31]

Answer:

y = 0.03x + 70

Slope here represents the variation in the charges with the change in the number of flyers

Positive slope means that the cost is increasing with increase in number of flyers

Step-by-step explanation:

Given:

for 100 copies advertiser is charged = $73

For 400 copies advertiser is charged = $82

Now,

here the charge is a function of number of flyers

we have the general line equation for a linear relationship as:

y = mx + c

here m is the slope

c is the constant

for the first case we have

y = $73

x = 100

thus,

73 = 100m + c ...........(1)

for the second case, we have

y = $82

x = 400

thus,

82 = 400m + c ...........(2)

subtracting (1) from (2)

82 = 400m + c

- ( 73 = 100m + c )

==================

9 = 300m + 0

or

m = 0.03

substituting the value of slope in equation (1)

73 = 100 × 0.03 + c

73 = 3 + c

or

c = 70

Hence,

the equation is y = 0.03x + 70

here y is amount charged and x are the number of flyers.

Slope here represents the variation in the charges with the change in the number of flyers

Positive slope means that the cost is increasing with increase in number of flyers

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The maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. A truck measures 162 inches in height.

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It would not pass under the bridge because ig you divide 162 by 12 it would equal 13.5

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Step-by-step explanation:

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3 years ago

A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec

Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (<em>n</em> ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

$Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18$

The sample size is, <em>n</em> = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

$\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191$

(a)

The null hypothesis is:

<em>H</em>₀: The usual load is 13 credits, i.e. <em>μ</em> = 13.

Assume that the significance level of the test is, <em>α</em> = 0.05.

Construct a (1 - <em>α</em>) % confidence interval for population mean to check the claim.

The (1 - <em>α</em>) % confidence interval for population mean is given by:

$CI=\bar x\pm z_{\alpha/2}\times SE$

For 5% level of significance the two tailed critical value of <em>z</em> is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct the 95% confidence interval as follows:

$CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)$

As the null value, <em>μ</em> = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

$P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z$

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

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2 years ago

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