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cupoosta [38]
3 years ago
5

Use the net to complete the surface area of the three dimensional figure a.126 units b.132 units c.154 units d.202 units

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer:its B

Step-by-step explanation:

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Need help please and thank you
Juli2301 [7.4K]
It would be C because it’s asking you to multiple 3/4 by 3/4 sense there is a 2 exponent. And in order to multiply fractions you multiply across the top and bottom and then simplify. Sense c is already simplified that would be your answer. 3 x 3
4x4 9/16 or c
3 0
2 years ago
Can you help me find length bc please!!!!
masya89 [10]

Remark

You are dealing with a right angle triangle. You can use one of Sin(x) Cos(x) or Tan(x). Since the Hypotenuse is involved and since you are given the adjacent side, Cos(71) is what you will need.

Solution

H = BC

Cos(x) = adjactent / hypotenuse

Cos(71) = 6.3 / H            Multiply both sides by H

H * Cos(71) = 6.3            Divide by Cos(71)

H = 6.3 / cos(71)             Cos(71) = 0.32557

H = 6.3 / 0.32557          Divide

H = BC = 19.351                       Answer

6 0
3 years ago
13. Find the equations of the straight lines which passes
ipn [44]

9514 1404 393

Answer:

  • y = 1/2x +2
  • y = -2x +7

Step-by-step explanation:

The slope of a line is the tangent of the angle it makes with the x-axis. The given line has a slope of -1/3, so the lines we want will have slopes of ...

  m1 = tan(arctan(-1/3) +45°) = 0.5 . . . . . using a calculator

  m2 = tan(arctan(-1/3) -45°) = -2

Of course, these two lines are perpendicular to each other, so their slopes will have a product of -1: (0.5)(-2) = -1.

__

We can use the point-slope form of the equation for a line to write the desired equations:

  y = m(x -h) +k . . . . . line with slope m through point (h, k)

<u>Line 1</u>:

  y = 1/2(x -2) +3

  y = 1/2x +2

<u>Line 2</u>:

  y = -2(x -2) +3

  y = -2x +7

3 0
3 years ago
The half-life of the radioactive element unobtanium-43 is 10 seconds. If 48 grams of unobtanium-43 are initially present, how ma
natka813 [3]

Answer:

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

Step-by-step explanation:

Given;

initial mass of the radioactive element  = 48 grams

half life, t = 10 seconds

time of decay (s)                          remaining mass of the  radioactive element

0 ------------------------------------------------- 48 grams

10------------------------------------------------- 24 grams

20 ------------------------------------------------- 12 grams

30 -------------------------------------------------- 6 grams

40 --------------------------------------------------- 3 grams

50 ----------------------------------------------------- 1.5 grams

60------------------------------------------------------0.75 grams

Thus;

At time, 10 seconds, the mass remaining is 24 grams

At time, 20 seconds, the mass remaining is 12 grams

At time, 30 seconds, the mass remaining is 6 grams

At time, 40 seconds, the mass remaining is 3 grams

At time, 50 seconds, the mass remaining is 1.5 grams

7 0
3 years ago
In the diagram below, the radii of the two concentric circles are 3 centimeters and 7 centimeters, respectively.
True [87]

Answer:

125.6 cm²

Step-by-step explanation:

Area of the shaded region = area of larger circle - area of the smaller circle

Area of the smaller circle = πr²

π = 3.14, r = 3 cm

Area of smaller circle = 3.14*3² = 3.14*9 = 28.26 cm²

Area of larger circle = πr²

π = 3.14, r = 7

Area of larger circle = 3.14*7² = 3.14*49 = 153.86 cm²

Area of the shaded region = 153.86 - 28.26 = 125.6 cm²

5 0
2 years ago
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