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Marianna [84]
3 years ago
14

Tata Darka ma 20 m siatki ogrodzeniowej.Jakie wymiary w metrach,wyra¿one liczbami naturalnymi,powinien mieæ prostok¹tny warzywni

k aby mo¿na by³o go ogrodziæ tak¹ siatk¹ oraz ¿eby jego pole by³o jak najwiêksze.
Mathematics
1 answer:
grin007 [14]3 years ago
5 0

Answer:

Hence the dimensions are 5×5 i.e. 5 meters and 5 meters such that its field would be as large as possible.

Step-by-step explanation:

Darek's dad has a 20 m fencing mesh.

Since we have to make a rectangular garden with he help of fencing the garden using this mesh, that means perimeter of this garden is 20 m.

i.e. 2( l+b)=20

also we have to fenced in such a way that its field would be as large as possible.

ie. it has the largest Area.

Now we will start from the dimensions possible as:

9×1 whose area will 9 m^2 (since Area=l×b)

Next dimension will be:

8×2 whose area will be 16 m^2

Next will be:

7×3 whose area will be 21 m^2

Next will be:

6×4 whose area will be 24 m^2

Next will be:

5×5 whose area will be 25 m^2

Next will be:

4×6 whose area will be same as of 6×4.

Hence, we get the maximum area to be 25 m^2 which is obtained when the dimensions are 5×5.



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Answer:

The test statistic for the appropriate test is \frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}.

Step-by-step explanation:

The experiment conducted here is to determine whether there is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. north and south.

The hypothesis to test this can be defined as follows:

<em>H₀</em>: There is no difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. <em>p</em>₁ = <em>p</em>₂.

<em>Hₐ</em>: There is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. <em>p</em>₁ ≠ <em>p</em>₂.

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A sample of <em>n</em> = 40 starfishes are selected from both the ocean areas.

It provided that of the 40 starfish from the north, 6 were found to be over 8 inches in length and of  the 40 starfish from the south, 11 were found to be over 8 inches in length.

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Compute the sample proportion of starfish from south that were over 8 inches in length as follows:

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The test statistic is:

z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}

Compute the combined proportion <em>P</em> as follows:

P=\frac{X_{n}+X_{s}}{n_{n}+n_{s}}=\frac{6+11}{40+40}=0.2125

Compute the test statistic value as follows:

z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}

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Thus, the test statistic for the appropriate test is \frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}.

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