A rectangle is twice as long as it is wide, and has a perimeter of 48 inches, what is the area of the rectangle?
2 answers:
Answer: A = 128 in^2
Explanation:
Assume:
X is the width
And 2x is the length
We know Perimeter = 48
P = 2(x + 2x) = 48
2x + 4x = 48
6x = 48
x = 8
Now we found the width which is 8
And the length is 2 times the width which is 8 x 2 = 16
Now that we have both length and width we can find the area
A = 16 x 8 = 128
Answer:
Step-by-step explanation:
P = 2w + 2l
l = 2w
48 = 2w + 2×2w
48 = 2w + 4w
48 = 6w
w = 48 : 6
w = 8 inches
l = 2w
l = 2×8inches
l = 16 inches
A = w×l
= 8in × 16in
= 128 inches²
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