A rectangle is twice as long as it is wide, and has a perimeter of 48 inches, what is the area of the rectangle?

2 answers:

5 0

Answer: A = 128 in^2

Explanation:
Assume:
X is the width
And 2x is the length

We know Perimeter = 48

P = 2(x + 2x) = 48
2x + 4x = 48
6x = 48
x = 8

Now we found the width which is 8
And the length is 2 times the width which is 8 x 2 = 16

Now that we have both length and width we can find the area

A = 16 x 8 = 128

Margarita [4]2 years ago

5 0

Answer:

128 inches²

Step-by-step explanation:

P = 2w + 2l

l = 2w

48 = 2w + 2×2w

48 = 2w + 4w

48 = 6w

w = 48 : 6

w = 8 inches

l = 2w

l = 2×8inches

l = 16 inches

A = w×l

= 8in × 16in

= 128 inches²

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