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3 years ago

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A rectangle is twice as long as it is wide, and has a perimeter of 48 inches, what is the area of the rectangle?

2 answers:

IceJOKER [234]3 years ago

5 0

Answer: A = 128 in^2

Explanation:
Assume:
X is the width
And 2x is the length

We know Perimeter = 48

P = 2(x + 2x) = 48
2x + 4x = 48
6x = 48
x = 8

Now we found the width which is 8
And the length is 2 times the width which is 8 x 2 = 16

Now that we have both length and width we can find the area

A = 16 x 8 = 128

Margarita [4]3 years ago

5 0

Answer:

128 inches²

Step-by-step explanation:

P = 2w + 2l

l = 2w

48 = 2w + 2×2w

48 = 2w + 4w

48 = 6w

w = 48 : 6

w = 8 inches

l = 2w

l = 2×8inches

l = 16 inches

A = w×l

= 8in × 16in

= 128 inches²

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timofeeve [1]

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Step-by-step explanation:

Given :

$f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8$

Point of intersection :

$f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}$

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Equation of line passing through two points $\left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right )$ is given by $y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )$

Let $\left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )$

So, equation is as follows :

$y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0$

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4 years ago

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Answer:

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<u>The length of the model:</u>

87*1/4 in = 21 3/4 in = 21.75 in

Correct choice is B

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3 years ago

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Answer:

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Step-by-step explanation:

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