THEOREM:
- h² = p² + b² where h is hypotenuse, b is base and p is perpendicular.
ANSWER:
[3] By pythagorean theorem,
- x² = 14² + 9²
- x² = 196 + 81
- x² = 277
- x = √277
- x = 16.64 rounded.
[4] By pythagorean theorem,
- x² = 32² + 24²
- x² = 1024 + 576
- x² = 1600
- x = √1600
- x = 40.
[5] By pythagorean theorem,
- (2x)² = 21² – 12.6²
- 4x² = 441 – 158.76
- 4x² = 284.24
- x² = 284.24/4 = 70.56
- x = √70.56
- x = 8.4
[6] By tangent property,
- 7x – 29 = 2x + 16
- 7x – 2x = 16 + 29
- 5x = 45
- x = 9.
So, WX = 7(9) – 29 = 63 – 29
Answer:
Let X be the number of times the target is hit. The probability P(X≥1) then equals 1 minus the probability of missing the target three times:
P(X≥1) = 1− (1−P(A)) (1−P(B)) (1−P(C))
= 1−0.4*0.3*0.2
= 0.976
To find the probability P(X≥2) of hitting the target at least twice, you can consider two cases: either two people hit the target and one does not, or all people hit the target. We find:
P(X≥2)=(0.4*0.7*0.8)+(0.6*0.3*0.8)+(0.6*0.7*0.2)+(0.6*0.7*0.8) = 0.788
Step-by-step explanation:
7 1/4 - 2 4/5
Turn the denominator into a common denominator for both fractions:
7 5/20 - 2 16/20
To subtract easier, turn the fractions into an improper fraction:
145/20 - 56/20
Subtract the numerators:
145 - 56 = 89 ---> 89/20
Simplify (to get an answer of):
4 9/20
Add labels:
Joseph has 4 9/20 ounces of candy left
I might be able to give you a hand here!
