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2 years ago

Nate's recipe calls for 3 cups of flour, but all of his

Mathematics

1 answer:

Rainbow [258]2 years ago

6 0

He should use 48 tablespoons of flour in his recipe.

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What is the average of 17/15

blondinia [14]

The average of 17 and 15 is 16 because if you add 17 and 15 together, and you divide them by 2, you get 16.

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3 years ago

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During the first 3 days of the week, Mike read an average of 28 pages per day. During the next 4 days, Mike averaged 42 pages pe

Anestetic [448]

Answer:

36 pages per day on average

Step-by-step explanation:

Calculate the average.

3 * 28 (The first 3 days of the week where Mike reads 28 pages per day) = 84

4 * 42 (The next 4 days where Mike reads 42 pages per day ) = 168

168 + 84 = 252

To find the average using this total, divide it by the total amount of days of reading (seven days in this problem).

252 / 7 = 36

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1 year ago

What name is given to the price dealerships pay for vehicles

german

Answer:

The answer is...

Step-by-step explanation:

Cost

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3 years ago

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Bject?

Yakvenalex [24]

Answer:

The entire volume would be 60m, but if it's talking only about the little rectangle on top then the answer is 6m.

Step-by-step explanation:

The length of the smaller object is 1m, the height is 2m, and the width is 3m (as seen to the right side near the bigger block).

Multiply all those numbers together (1×2=2, 2×3=6 or just simply 1×2×3=6)

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2 years ago

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Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

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3 years ago