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2 years ago

Nate's recipe calls for 3 cups of flour, but all of his

Mathematics

1 answer:

Rainbow [258]2 years ago

6 0

He should use 48 tablespoons of flour in his recipe.

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Let Y be a random variable with a density function given by

Neporo4naja [7]

From the given density function we find the distribution function,

$F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y$

(a)

$F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)$

$\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1$

$\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}$

(b)

$F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y$

$\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2$

$\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}$

(c)

$F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})$

$\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3$

$\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}$

5 0

3 years ago

A 3. A card is pulled from a standard deck of cards.

dexar [7]

<h3>Answer: 4/13</h3>

Explanation:

There are 13 hearts, including the queen of hearts. Then there are 3 more queens to get us to 13+3 = 16 cards we're after.

There are 16 cards we want out of 52 total, so the probability is 16/52 = (4*4)/(4*13) = 4/13

3 0

2 years ago

Find the 11" term of the following geometric sequence.<br> 5, 15, 45, 135, ...

vladimir1956 [14]

5*3^0 = 5,

5*3^1 = 15,

5*3^2 = 45,

5*3^3 = 135,

5*3^4 = 405
1.9K viewsView upvotes

5

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2x + 4y = 14 and 3x – 4y = -39 solve by elimination

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Answer: x=-5 and y=6

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