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3 years ago

8. Sabrina uses 9 inches of ribbon to make one bow. Sabrina buys 7 packets

Mathematics

1 answer:

joja [24]3 years ago

3 0

Answer:

The answer is B, 126.

Step-by-step explanation:

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A town uses positive numbers to track increases in population and negative numbers to track decreases in population. The populat

Snowcat [4.5K]

Answer:

Im bored wanna talk?

Step-by-step explanation:

7 0

3 years ago

Need help on solving problems with comon tangents

Orlov [11]

First, find angle ECD using tan^-1(6/4), we get angle as 56.31

Now by proportionate, angle ECD and angle EBA are equal.

Hence you can use tan to find AB i.e, AB = 18/tan(56.31)= 12

Therefore, AB = 12

3 0

3 years ago

A grocery bag can withstand 300 n of force before it rips apart. how many kilograms of apples can it safely hold?

lidiya [134]

By definition, the weight is given by
F = m * g
Where,
m = mass
g = gravity.
We must then clear the mass:
m = F / g
Substituting the values
m = (300) / (9.81) = 30.58Kg
Answer
the bag can safely hold 30.58Kg of apples

8 0

3 years ago

What is 9 + 10 wrong answers only

astra-53 [7]

Answer:

A car

Step-by-step explanation:

4 0

3 years ago

List the possible rational roots and actual rational roots for the equation x^3+2x^2-5x-6=0

Lesechka [4]

Answer:

$\boxed{\textsf{ The possible rational roots of equation are \textbf{ 2 , (-1) and (-3)}.}}$

Step-by-step explanation:

A cubic polynomial is given to us . And we need to find the rational roots . Rational roots means the roots which really exits and not imaginary . The given polynomial is :-

$\sf\implies p(x)= x^3+2x^2-5x-6$

On equating it with 0 , it becomes cubic equation. That is ,

$\sf\implies x^3+2x^2-5x-6=0$

Here we will factorise out the given equation and then equate it with 0 to find the roots . Here the constant term is 6 . So the possible factors is 6 is :-

$\sf\implies Factors\ of \ 6 \ = \ \pm 1 , \pm 2 , \ \pm 3 , \ \pm 6.$

So put them one by one checking out the factors .

Put x = 2 :-

$\sf\implies p(x)= x^3+2x^2-5x-6\\\\\sf\implies p(2)= 2^3 +2(2)^2 -5(2)-6\\\\\sf\implies p(2)= 8 +8 -10 -6 \\\\\sf\implies p(2)=16-16\\\\\sf\implies \boxed{\sf p(2)= 0 }$

This implies that (x-2) is a factor of p(x) . Now let's divide the polynomial by (x-2) .

$\rule{200}2$

x-2 ) x³ + 2x² - 5x -6 ( x² +4x +3

⠀⠀⠀ (-) x³(+) -2x²

_____________

⠀⠀⠀+4x² -5x - 6

⠀⠀⠀ (-) 4x² (+) -8x

_____________

⠀⠀⠀ 3x -6

⠀⠀⠀(+) 3x(+) - 6

_______________

⠀⠀⠀⠀ 0

Hence we can write , x³ +2x² -5x -6 as ,

$\sf\implies x^3+2x^2-5x-6 = (x-2)(x^2 +4x+3)$

Equating it with 0 .

$\sf\implies x^3+2x^2-5x-6 = 0\\\\\sf\implies (x-2)(x^2 +4x+3) = 0 \\\\\sf\implies (x-2)(x^2+3x+x+3)=0 \\\\\sf\implies (x-2)[ x(x+3)+1(x+3)]=0 \\\\\sf\implies (x-2)(x+1)(x+3)=0 \\\\\sf\implies\boxed{\pink{\frak { x = 2 , (-1) , (-3) }}}$

8 0

3 years ago