The most direct way for jonathon to gain on-the-job experience and earn money while attending school is to apply for: D:a work-study program
When there are conflicting GPOS, the order in which they're evaluated and applied are: Site, Domain, and OU.
<h3>What is the conflict about?</h3>
Note that when trying to know which policy settings to apply, the local policy of the machine is said to be examined, followed by site policies, then domain policies, and lastly the policies on all the OUs that has all the object being processed.
Therefore, When there are conflicting GPOS, the order in which they're evaluated and applied are: Site, Domain, and OU.
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Answer:
D
Explanation:
I don't know the language, but it is clear what is going on.
It looks like you are defining a value for a in both commands.
a.multiply(b); looks like you take the value in a (which is 10) multiply it by 25 and put the result back in a. So so far we have 10 * 25 = 250
Note the next command
a.add(b)
looks like you take the current value in a(which is now 250)
and put the value of b (which has not been changed. It is still 25) and put that in a (which is 250).
The result is 250 + 25 = 275
The answer is D. Since I only understand the logic, if this answer is wrong, I wish you'd leave a note.