We are standing on the top of a 1200 feet tall building and launch a small object upward. the object's vertical position, measur
ed in feet, after t seconds is h(t)=−16t2+160t+1200. what is the highest point that the object reaches?
2 answers:
Answer:
h = 1600 feet
Step-by-step explanation:
To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.
Please see the attached image below, to find more information about the graph
The projectile formula is
h(t) = a*t^2 + v*t + h0
Where,
v = initial vertical velocity of the object in feet per second
h0 = initial height of the object in feet
h(t) = −16t^2 +160t + 1200
If we look at the graph, we can find the point in which the height becomes maximum.
For this problem,
h = 1600 feet ,
at t = 5 seconds
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