We are standing on the top of a 1200 feet tall building and launch a small object upward. the object's vertical position, measur
ed in feet, after t seconds is h(t)=−16t2+160t+1200. what is the highest point that the object reaches?
2 answers:
Answer:
h = 1600 feet
Step-by-step explanation:
To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.
Please see the attached image below, to find more information about the graph
The projectile formula is
h(t) = a*t^2 + v*t + h0
Where,
v = initial vertical velocity of the object in feet per second
h0 = initial height of the object in feet
h(t) = −16t^2 +160t + 1200
If we look at the graph, we can find the point in which the height becomes maximum.
For this problem,
h = 1600 feet ,
at t = 5 seconds
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Answer: The answer is (D) Reflection across the line y = -x.
Step-by-step explanation: In figure given in the question, we can see two triangles, ΔABC and ΔA'B'C' where the second triangle is the result of transformation from the first one.
(A) If we rotate ΔABC 180° counterclockwise about the origin, then the image will coincide with ΔA'B'C'. So, this transformation can take place here.
(B) If we reflect ΔABC across the origin, then also the image will coincide with ΔA'B'C' and so this transformation can also take place.
(C) If we rotate ΔABC through 180° clockwise about the origin, the we will see the image will be same as ΔA'B'C'. Hence, this transformation can also take place.
(D) Finally, if we reflect ΔABC across the line y = -x, the the image formed will be different from ΔA'B'C', in fact, it is ΔA'D'E', as shown in the attached figure. So, this transformation can not take place here.
Thus, the correct option is (D).
