All categories

3 years ago

Tp-3 which class of trailer hitch is best suited for a boat and its equipment weighing less than 2,000 pounds?

1 answer:

5 0

Trailer Hitches are categorized into a five classes I, II, III, IV and V. Trailer ratings are based on the total weight of the trailer or boat.
Class I trailer hitch is best suited for a boat and its equipment weighing less than 2,000 pounds and class II trailer <span>hitch is best suited for a boat and its equipment weighing 2,000 pounds or greater up to 3500 pounds. Class III, IV and V have their own range.
</span>

You might be interested in

Objects of equal mass are oscillating up and down in simple harmonic motion on two different vertical springs. The spring consta

Zanzabum

Answer:

$k_2=920\ N/m$

Explanation:

Given that,

The spring constant of spring 1, $k_1=230\ N/m$

The motion of the object on spring 1 has twice the amplitude as the motion of the object on spring 2, $A_1=2A_2$

As the magnitude of the maximum velocity is the same in each case, it means the maximum kinetic energy is same in each case. In other words, the total energy is same.

$\dfrac{1}{2}k_1A_1^2=\dfrac{1}{2}k_2A_2^2$

$k_1A_1^2=k_2A_2^2$

$k_1(2A_2)^2=k_2A_2^2$

$k_2=920\ N/m$

So, the spring constant of spring 2 is 920 N/m. Hence, this is the required solution.

3 0

3 years ago

A student uses a meter to measure 120 coulombs flowing through a circuit in 60 seconds. what is the current in this circuit?

Keith_Richards [23]

A student uses a meter to measure 120 coulombs flowing through a circuit in 60 seconds. The electric current in this circuit will be 2 A

Current is a flow of electrical charge carriers, usually electrons or electron-deficient atoms. The common symbol for current is the uppercase letter I. The standard unit is the ampere, symbolized by A.

current = charge / time

given

time = 60 seconds

charge = 120 Coulombs

current = Q / T = 120 / 60 = 2 A

To learn more about electric current here

brainly.com/question/12791045

#SPJ4

3 0

2 years ago

The curved movement of air or water is the result of which of these?

ella [17]

<h3><u>Answer;</u></h3>

B. the rotation of Earth on its axis

<h3><u>Explanation;</u></h3>

<em><u>The Coriolis effect describes how the Earth's rotation steers winds and surface ocean currents. The Coriolis effect causes the motion of a freely moving object to appear as a curve.</u></em>
<em><u>Therefore, since air and water move freely, the Coriolis effect makes their movement to be curved. This is why the movement of winds and oceans does not follow a straight line but it is bent and curved.</u></em>

8 0

4 years ago

Read 2 more answers

develop an equation with a proportionality constant that describes the relationship between the gravitational force the mass of

Ganezh [65]

Let the mass of planet and moon be Mp and Mn respectively.
And the distance between them is "r"

Then according to Newton's law of gravitation,

The force with which the planet and the moon attract esch other is
1) directly proportional to the product of their masses i.e. Mp * Mn

2) inversly proportional to the square of the distance between them i.e r ^2

Therefore,F =. G (Mp* Mn)/r^2
Where,G is gravitational constant

3 0

4 years ago

A particle initially located at the origin has an acceleration of a=3jm/s^2 and an initial velocity of Vi=5im/s.

-BARSIC- [3]

Given the particle's acceleration is

$\vec a(t) = \left(3\dfrac{\rm m}{\mathrm s^2}\right)\vec\jmath$

with initial velocity

$\vec v(0) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath$

and starting at the origin, so that

$\vec r(0) = \vec 0$

you can compute the velocity and position functions by applying the fundamental theorem of calculus:

$\vec v(t) = \vec v(0) + \displaystyle \int_0^t \vec a(u)\,\mathrm du$

$\vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u)\,\mathrm du$

We have

• velocity at time <em>t</em> :

$\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \displaystyle \int_0^t \left(3\dfrac{\rm m}{\mathrm s^2}\right)\,\vec\jmath\,\mathrm du \\\\ \vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath \\\\ \boxed{\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath}$

• position at time <em>t</em> :

$\vec r(t) = \displaystyle \int_0^t \left(\left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)u\,\vec\jmath\right) \,\mathrm du \\\\ \boxed{\vec r(t) = \left(5\dfrac{\rm m}{\rm s}\right)t\,\vec\imath + \frac12 \left(3\frac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath}$

8 0

3 years ago