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2 years ago

What waves need molecules in order to transfer energy

Physics

1 answer:

nevsk [136]2 years ago

4 0

Answer:

Mechanical waves

Explanation:

Waves are periodic oscillations, that carry energy, but not matter.

Waves are classified into two types:

- Mechanical waves: these waves are produced by the oscillations of the particles in a medium, which can oscillate along the direction of propagation of the wave (longitudinal wave) or perpendicular to the direction of motion of the wave (transverse wave). These waves can only propagate in a medium, so they cannot travel in a vacuum. Examples of mechanical waves are sound waves.

- Electromagnetic waves: these waves are produced by the oscillations of electric and magnetic field. They are transverse waves. They are the only type of wave able to propagate through a vacuum (so, through space).

Therefore, the waves that need molecules in order to transfer energy are mechanical waves.

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A battery is connected to a 10 resistor and produces a current of 0.2 A in the circuit. If the resistor is replaced with a 20 re

drek231 [11]

Answer:

0.1 A

Explanation:

From the question,

V = IR............ Equation 1

Where V = Voltage, I = current, R = Resistance.

Given: I = 0.2 A, R = 10 ohms.

Substitute into equation 1

V = 0.2(10)

V = 2 volt,

If the resistor is replaced with a 20 resistor, The nwe current is

I = V/R................ Equation 2

I = 2/20

I = 0.1 A

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2 years ago

A force F with arrow applied to an object of mass m1 produces an acceleration of 3.10 m/s2. The same force applied to a second o

Bas_tet [7]

Answer:

(a) The value of the ratio m₁/m₂ is 0.581

(b) the acceleration of the combined masses is 1.139 m/s²

Explanation:

Given;

The acceleration of force applied to M₁, a₁ = 3.10 m/s²

The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²

Let this force = F

According Newton's second law of motion;

F = ma

(a) the value of the ratio m₁/m₂

since the applied force is same in both cases, M₁a₁ = M₂a₂

$\frac{m_1}{m_2} = \frac{a_2}{a_1} \\\\\frac{m_1}{m_2} = \frac{1.8}{3.1} \\\\\frac{m_1}{m_2} = 0.581$

(b) the acceleration of m₁ and m₂ combined as one object under the action force F

F = ma

$a = \frac{F}{M} \\\\a = \frac{F}{m_1 + m_2} \\\\a = \frac{F}{0.581m_2 + m_2}\\\\a = \frac{F}{1.581m_2}$

$But, m_2 = \frac{F}{a_2} \\\\a = \frac{F}{1.581m_2} = \frac{F*a_2}{1.581F} \\\\a = \frac{a_2}{1.581} \\\\a = \frac{1.8}{1.581} = 1.139 \ m/s^2$

Therefore, the acceleration of the combined masses is 1.139 m/s²

5 0

2 years ago

An electron and a positron are located 17 m away from each other and held fixed by some mechanism. The positron has the same mas

mariarad [96]

Answer:

Velocity will be 13.9 m/s when they are 1.3 m away from each other.

Explanation:

Detailed steps are attached below.

6 0

3 years ago

What is the key difference between mechanical and electromagnetic waves

Alecsey [184]

Mechanical waves require a medium to travel, but electromagnetic waves do not.

7 0

2 years ago

Two wires are made of the same material. Wire 1 has length that is 1.35 times the length of wire 2 and diameter that is 0.91 tim

Oksi-84 [34.3K]

Answer:

1.117935:1

Explanation:

Since the wires are of the same material, they will have the same resistivity $\rho$ .

The cross-sectional area of the of a wire is given by;

$A=\pi\frac{d^2}{4}................(1)$

where d is the diameter of the wire.

Also, the relationship between resistance R, cross-sectional area A and length l of a wire is given as follows;

$\rho=\frac{RA}{l}..................(2)$

Since the resistivity same for both wires, say wire 1 and wire 2, we can wreite the following;

$\frac{R_1A_1}{l_1}=\frac{R_2A_2}{l_2}..................(3)$

Hence from eqaution (3), the ration of wire 1 to 2 is expressed as;

$\frac{R_1}{R_2}=\frac{l_1A_2}{l_2A_1}..................(4)$

Given;

$l_1=1.35l_2$

$\frac{R_1}{R_2}=\frac{1.35l_2A_2}{l_2A_1}\\\frac{R_1}{R_2}=\frac{1.35A_2}{A_1}.............(5)$

We then use equation (1) to fine the ratio of the area $A_1$ to $A_2$

bearing in mind that $d_1=0.91d_2$

This ratio gives 0.8281. Substituting this into equation (5), we get the following;

$\frac{R_1}{R_2}= 1.35*0.8281=1.117935$

4 0

2 years ago

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