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Ymorist [56]
3 years ago
8

one of the four wave interactions is very important to how plants use light to grow. guess which interaction this is

Physics
1 answer:
KiRa [710]3 years ago
6 0
The photosynthetic wave interaction between visible light and a photosensitive part of a plant is very important t how plants use light to grow. 
The frequency range and intensity levels of this light, I don't know. 

Maybe the above ???
You might be interested in
A roofer drops a nail that hits the ground traveling at 26 m/s. How fast was the nail traveling 1 second before it hits the grou
ELEN [110]
This problem can be solved using a kinematic equation. For this case, the following equation is useful:

v_final = v_initial + at

where,
v_final = final velocity of the nail
v_initial = initial velocity of the nail
a = acceleration due to gravity = 9.8 m/s^2
t = time 

First, we determine the time it takes for the nail to hit the ground. We know that the initial velocity is 0 m/s since the nail was only dropped. It has a final velocity of 26 m/s. We substitute these values to the equation and solve for t:

26 = 0 + 9.8*t
t = 26/9.8 = 2.6531 s

The problem asks the velocity of the nail at t = 1 second. We then subtract 1 second from the total time 2.6531 with v_final as unknown.

v_final = 0 + 9.8(2.6531-1) = 16.2004 m/s.

Thus, the nail was traveling at a speed of 16. 2004 m/s, 1 second before it hit the ground. 

5 0
4 years ago
A(n) ? can be used to represent the direction and strength of a force
ExtremeBDS [4]
Units of force are the newton pound.
6 0
3 years ago
Read 2 more answers
What is an effector strain of bacteria
GarryVolchara [31]
The effector strain of bacteria is that the bacteria would colonize on the teeth and help prevent the child from developing cavitie
7 0
3 years ago
At a waterpark, sleds with riders are sent along a slippery, horizontal surface by the release of a large, compressed spring. Th
steposvetlana [31]

The sleds speed when the spring returns toits uncompressed length is v = 0.03 m/s.

<u>Explanation</u>:

Given,

force constant = 42 N/cm = 0.42 N/m,   mass m = 68 kg, spring x = 0.39 m

The potential energy, U, stored in the spring is

                     U = 1/2 kx^2  

                       = 1 / 2 \times 0.42 \times (0.39)^2

                       = 0.032 J

All its potential energy has been converted into kinetic energy since it has a uncompressed length.

                    K = 1/2 mv^2

                     v = sqrt (2K / m)

                       = √(( 2 \times 0.032) / 68)

                    v = 0.03 m/s .

4 0
4 years ago
Distance in scientific notation
n200080 [17]

Answer:

(See explanation for further information)

Explanation:

a) The distances of each planet with respect to the Sun is:

Mercury - 57.909 \times 10^{6}\,mi

Venus - 67.240\times 10^{6}\,mi

Earth - 92.960\times 10^{6}\,mi

Mars - 141.600\times 10^{6}\,mi

Jupiter - 483.800\times 10^{6}\,mi

Saturn - 888.200\times 10^{6}\,mi

Uranus - 1,787\times 10^{6}\,mi

Neptune - 2,795\times 10^{6}\,mi

b) The solutions are presented below:

A. The distance between Venus and Jupiter is:

\Delta s = 483.800\times 10^{6}\,mi-67.240\times 10^{6}\,mi

\Delta s = 416.560\times 10^{6}\,mi

B. The combined distance from the Sun is:

\Delta s = 57.909\times 10^{6}\,mi + 67.240\times 10^{6}\,mi +92.960\times 10^{6}\,mi

\Delta s = 218.109\times 10^{6}\,mi

Which is less than the distance from the Sun to Neptune (2,795\times 10^{6}\,mi).

C. The new distance of Earth is 929.60 \times 10^{6}\,mi (929,600,000\,mi). Saturn would be the closest planet to Earth, whose distance:

Scientific notation:

\Delta s = 929.600\times 10^{6}\,mi-888.200\,\times 10^{6}\,mi

\Delta s = 41.4\times 10^{6}\,mi

Standard notation:

\Delta s = 929,600,000\,mi - 888,200,000\,mi

\Delta s = 41,400.000\,mi

3 0
4 years ago
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