You are given two points in the linear function. At time 0 years, the value is $3000. At time 4 years, the value is $250. This means you have points (0, 3000) and (4, 250). You need to find the equation of the line that passes through those two points.
y = mx + b
m = (y2 - y1)/(x2 - x1) = (3000 - 250)/(0 - 4) = 2750/(-4) = -687.5
Use point (0, 3000).
3000 = -687.5(0) + b
b = 3000
The equation is
y = -687.5x + 3000
Since we are using points (t, v) instead of (x, y), we have:
v = -687.5t + 3000
Answer: d. v = -687.50 t + 3,000
Answer:
a =13/5
Step-by-step explanation:
f(x) = 6x − 5
f(5a) = 6*5a − 5=73
30a -5 = 73
Add 5 to each side
30a -5+5 = 73+5
30a =78
Divide by 30
30a/30 = 78/30
a =13/5
The axioms in addition help in developing theorems about multiplication because multiplication, in simple terms, repeated addition.
As an example,
This addition operation
3 + 3 + 3 + 3 = 12
can be expressed as a multiplication operation
3 x 4 = 12
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