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3 years ago

Which equation can be used to calculate the area of the shaded triangle in the figure below?

Mathematics

2 answers:

Whitepunk [10]3 years ago

7 0

It's the last option.

The area of a triangle can be calculated by multiplying the base and the height, and multiplying the product by 1/2.

nata0808 [166]3 years ago

5 0

Answer:

It is the last one!

Step-by-step explanation:

Flvs student right? first test for it!

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Tom drove at a constant speed 50 mph for 2.5 hours Albert drove at a constant speed of 65 mph for 2 hours. How many more total m

Alona [7]

Answer:

5 miles

Step-by-step explanation:

distance = speed · time

Tom's distance = (50 mi/h)·(2.5 h) = 125 mi

Albert's distance = (65 mi/h)·(2 h) = 130 mi

Albert drove 130 -125 = 5 miles farther than Tom.

8 0

2 years ago

Is it - or + 60 plz help me

Artemon [7]

+60 two negatives equal a positive

6 0

2 years ago

After being discounted 40%, a weather radio sells for $35.97. find the original price. (round your answer to the nearest cent.)

tia_tia [17]

It is given in the question that

After being discounted 40%, a weather radio sells for $35.97.

It means the weather radio sells at a 60% of original price.

Let the original price be $x.

Therefore according to the question,

$60% \ of \ x = 35.97
\\
0.6x = 35.97
\\
x = $59.95$

Therefore the original price of the weather radio is $59.95.

5 0

2 years ago

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vlabodo [156]

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

5 0

2 years ago

Read 2 more answers

How can the logarithmic expression be rewritten? Select True or False for each statement.

olasank [31]

Answer:

$1. log_3(cd)^4 = 4 log_3(c )+ log_3(d)$ FALSE

$2. \frac{2}{3} (ln(a) +ln(b)) = ln(\sqrt[3]{a^2b^2} )$ TRUE

$3.ln(\frac{e^3}{f} ) = 3 ln(e) - ln (f)$ TRUE

Step-by-step explanation:

Here, let us first state the logarithmic rules.

$log (a) - log (b) =log(\frac{a}{b} )\\log (ab) = log a + log b\\log(a^m) = m \times log (a)$

Now, here the given expressions are:

$1. log_3(cd)^4 = 4 log_3(c )+ log_3(d)$

The given statement is FALSE as:

$log_3(cd)^4 = 4 log_3(cd) = 4log_3(c) + 4log_3(d)$

$2. \frac{2}{3} (ln(a) +ln(b)) = ln(\sqrt[3]{a^2b^2} )$

$\frac{2}{3} (ln(a) +ln(b)) = \frac{2}{3} ln(ab) = ln(ab) ^\frac{2}{3} \\= ln(\sqrt[3]{a^2b^2} )\\\implies\frac{2}{3} (ln(a) +ln(b)) = ln(\sqrt[3]{a^2b^2} )$

The given statement is TRUE .

$3.ln(\frac{e^3}{f} ) = 3 ln(e) - ln (f)$

The given statement is TRUE as:

$ln(\frac{e^3}{f} ) = ln(e^3) - ln (f) = 3 ln(e) - ln (f)$

5 0

3 years ago